How can parse the url when encountering error "xml.parsers.expat.ExpatError: mismatched tag"?

How can parse the url when encountering error "xml.parsers.expat.ExpatError: mismatched tag"?

我想提取网页中元素 DOCUMENT 中的所有链接：

target to be parsed

import urllib.request
url = 'https://www.sec.gov/Archives/edgar/data/1326801/000132680120000013/0001326801-20-000013-index-headers.html'
ob=urllib.request.urlopen(url).read()
from xml.dom import minidom
xmldoc = minidom.parseString(ob)

遇到问题：

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python3.5/xml/dom/minidom.py", line 1968, in parseString
    return expatbuilder.parseString(string)
  File "/usr/lib/python3.5/xml/dom/expatbuilder.py", line 925, in parseString
    return builder.parseString(string)
  File "/usr/lib/python3.5/xml/dom/expatbuilder.py", line 223, in parseString
    parser.Parse(string, True)
xml.parsers.expat.ExpatError: mismatched tag: line 876, column 23

可能是格式错误的 xml 文件，如何用 minidom 加载它？

我不知道这个文件是什么，但它不是 XML，并且无法使用 XML 解析器进行解析。

是的，它不是 xml 文件，用 lxml.html 解析它，select 所有带有 xpath 的 url。

import urllib.request
url = 'https://www.sec.gov/Archives/edgar/data/1326801/000132680120000013/0001326801-20-000013-index-headers.html'
ob=urllib.request.urlopen(url).read()
doc = lxml.html.fromstring(ob)
links = doc.xpath('//pre/a')
for link in links:
    print(link.attrib['href'])