while 循环没有终止 python

Question

我正在编写一个交互式程序，在 select 选择选项后显示 y/n。如果在开始时我按 s 或 c while 循环终止。如果我 select some no first time "say 5" 第 5 个选项变为 y 但之后如果我按 "s" 或 "c" 它显示第 5 个条目为 "n" 并且程序没有退出。不知道出了什么问题。初学者问题。（替代解决方案也很受欢迎，也不能导入其他包）

import os,time
selected_list=[]
def px_filter_menu(num):
    os.system("clear")
    data = ["p1","p2","p3","p4","p5","p6","p7","p8","p9","p10","p11","p12","p13","p14","p15","p16","p17","p18","p19","p20","p21","p22","p23","p24","p25","p26"]

    print("============================================================================\n= Filter selection menu")
    print("============================================================================\n\n")

    gap =5

    for count , item in enumerate(data, 1):
        if count <10:
            if data[count-1] in selected_list:
                print("{0}.  {1} {2}".format(count,item.ljust(gap),"[y]"))
            else:
                print("{0}.  {1} {2}".format(count,item.ljust(gap),"[n]"))
        else:
            if data[count-1] in selected_list:
                print("{0}. {1} {2}".format(count,item.ljust(gap),"[y]"))
            else:
                print("{0}. {1} {2}".format(count,item.ljust(gap),"[n]"))

    print("\n\n[S] save and exit")
    print("\n\n[C] if you press C and wish to make changes please remove the PX and add again\n")

    input = raw_input("enter the desired number ")
    
    if len(input.strip()) ==0:
        print("first")
        time.sleep(2)
        px_filter_menu(-1)
       
    while True:
        if input.upper()=="S":
            print("5")
            time.sleep(2)
            break

        elif input.upper()=="C":
            del selected_list[:]
            #by default all protocol goes
            print("6")
            time.sleep(2)
            break

        elif input.isdigit() and data[int(input)-1] in selected_list:
            print(input)
            selected_list.remove(data[int(input)-1])
            print("3")
            time.sleep(2)
            px_filter_menu(-1)

        elif input.isdigit():
            selected_list.append(data[int(input)-1])
            print("4")
            time.sleep(2)
            px_filter_menu(-1)
        else:
            px_filter_menu(-1)
    return

px_filter_menu(-1)

Answer 1

问题在于，对于输入数字的情况，您会再次递归调用相同的函数。如果/当该调用退出时，执行将在此调用中继续，返回到 while 循环。

因为你有一个while循环，你不需要递归调用。如有必要，循环将处理重复的事情。

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