如何在 Django 中查询同一模型时 return 出现两条不同的错误消息
How to return two different error messages when querying the same model in Django
看看下面的内容:
def mutate(self, info, first_id, second_id):
try:
first = Model.objects.get(pk=first_id)
second = Model.objects.get(pk=second_id)
except Model.DoesNotExist:
return Exception('Object does not exist.')
else:
...
我如何 return 根据实际不存在的 ID 生成自定义错误消息?有这样的东西真是太好了:
{first_id} does not exist
我不能有两个不同的 except
积木,因为它是同一个模型。怎么办?
您可以简单地将查询分成两个语句:
def mutate(self, info, first_id, second_id):
try:
first = Model.objects.get(pk=first_id)
except Model.DoesNotExist:
raise Exception('Your first id {} Does not exist'.format(first_id))
try:
second = Model.objects.get(pk=second_id)
except Model.DoesNotExist:
raise Exception('Your second id {} Does not exist'.format(second_id))
...
PS:你需要raise
例外。不是 return 他们。
看看下面的内容:
def mutate(self, info, first_id, second_id):
try:
first = Model.objects.get(pk=first_id)
second = Model.objects.get(pk=second_id)
except Model.DoesNotExist:
return Exception('Object does not exist.')
else:
...
我如何 return 根据实际不存在的 ID 生成自定义错误消息?有这样的东西真是太好了:
{first_id} does not exist
我不能有两个不同的 except
积木,因为它是同一个模型。怎么办?
您可以简单地将查询分成两个语句:
def mutate(self, info, first_id, second_id):
try:
first = Model.objects.get(pk=first_id)
except Model.DoesNotExist:
raise Exception('Your first id {} Does not exist'.format(first_id))
try:
second = Model.objects.get(pk=second_id)
except Model.DoesNotExist:
raise Exception('Your second id {} Does not exist'.format(second_id))
...
PS:你需要raise
例外。不是 return 他们。