scandir 的相对路径处理

Relative Path Handling by scandir

函数 scandir 是否处理相对路径?

也就是说,下面两段代码是等价的吗?

int NUM = scandir("/home/hello/wait/../pqr/../../hello", &LIST, 0, alphasort);
int NUM = scandir("/home/hello", &LIST, 0, alphasort);

如果不是,是否有一些简单的内置函数可以将 /home/hello/wait/../pqr/../../hello 转换为 /home/hello

Does the function scandir handle relative paths?

我相信答案是肯定的。从 posix scandir 我们只知道:

The scandir() function shall scan the directory dir, [...]

来自posix定义:

3.129 Directory

A file that contains directory entries. No two directory entries in the same directory have the same name

scandir的参数是char *,所以它是一个字符串。从 posix 定义我们知道:

3.271 Pathname

A string that is used to identify a file. [...]

另一个名为 4.13 Pathname Resolution 的部分深入研究了路径名是如何解析的,并告诉我们:

If the pathname does not begin with a <slash>, the predecessor of the first filename of the pathname shall be taken to be either the current working directory of the process [...] (such pathnames are referred to as "relative pathnames").

所以因为 scandir 需要一个目录的路径名并且因为路径名是如何解析的,是的,你可以给 scandir 的相对路径。


In other words

这不是“其他词”——您显示的两个路径名都是绝对的,而不是相对的。在路径名中使用 dot-dot 不会使路径名成为相对路径。

are the following two pieces of code equivalent?

是的。


is there some simple buit-in function to convert /home/hello/wait/../pqr/../../hello to /home/hello?

没有"builtin function" to canonicalize a pathname in any compiler I am aware of. There exists a completely normal function provided from POSIX for that purpose and is called realpath(). GNU library may allocated the returned string dynamically and it also has canonicalize_file_name.