foreach 和 for 循环没有从 sql 查询中获取所有数据
foreach and for loop not getting all data from sql query
**已编辑
我将 sql 查询拆分为 3 个，现在查询如下所示。
$sql_2 = "SELECT DISTINCT cr.id AS courseid,
cr.fullname AS coursename,
cr.idnumber AS idnumber,
COUNT(DISTINCT ra.id) AS enrols,
COUNT(DISTINCT cc.timecompleted) AS completed
FROM {course} cr JOIN {context} ct ON ( ct.instanceid = cr.id )
LEFT JOIN {role_assignments} ra ON ( ra.contextid = ct.id ) and ra.roleid = 5
LEFT JOIN {course_completions} cc ON (cc.course = cr.id)
WHERE cr.id = :course_id GROUP BY cr.fullname, cr.id";
$sql_3 = "SELECT DISTINCT
u.id AS userid,
u.email AS email,
u.lastaccess,
c.id AS courseid
FROM {user} u
JOIN {role_assignments} ra ON ra.userid = u.id
LEFT JOIN {context} ct ON ct.id = ra.contextid AND ra.roleid = 5
LEFT JOIN {course} c ON c.id = ct.instanceid AND ct.contextlevel = 50
WHERE c.id = :course_id";
$sql_4 = "SELECT DISTINCT
u.id AS userid,
sc.name AS item,
m.name AS module,
cm.id AS cmid,
cm.idnumber AS itemidnumber,
sc.launch AS launch,
cmc.completionstate AS completed,
cmc.timemodified AS timecompleted
FROM {user} u
JOIN {role_assignments} ra ON ra.userid = u.id
LEFT JOIN {context} ct ON ct.id = ra.contextid AND ra.roleid = 5
LEFT JOIN {course} c ON c.id = ct.instanceid AND ct.contextlevel = 50
LEFT JOIN {course_modules} cm ON cm.course = c.id
LEFT JOIN {course_modules_completion} cmc ON cmc.userid = u.id AND cmc.coursemoduleid = cm.id
LEFT JOIN {modules} m ON m.id = cm.module
LEFT JOIN {scorm} sc ON sc.id = cm.instance
WHERE c.id = :course_id and m.id = 18";
$courses = $DB->get_records_sql($sql_2, ["course_id" => $requestedcourseids]);
$users = $DB->get_records_sql($sql_3, ["course_id" => $requestedcourseids]);
$modules = $DB->get_records_sql($sql_4, ["course_id" => $requestedcourseids]);
我在每个结果下添加了foreach和for循环得到多维数组结果得到了这样的模块结果
"course": [
{
"courseid": 4,
"coursename": "Activities",
"idnumber": "",
"enrols": 6,
"completed": 1,
"users": [
{
"userid": 3,
"email": "test1@hotmail.com",
"lastaccess": 1599379804,
"modules": [
{
"userid": 3,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": 1,
"timecompleted": 1595575023
},
{
"userid": 2,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": 0,
"timecompleted": 1593135761
},
{
"userid": 4,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": 1,
"timecompleted": 1589359945
},
{
"userid": 8,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": null,
"timecompleted": null
},
{
"userid": 7,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": null,
"timecompleted": null
}
]
},
{
"userid": 2,
"email": "test2@gmail.com",
"lastaccess": 1599635370,
"modules": [
{
"userid": 9,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": 1,
"timecompleted": 1595576987
},
{
"userid": 3,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": 1,
"timecompleted": 1595575023
},,,,
如您所见，模块列表仅显示一个具有每个用户 ID 的模块。
它应该为每个用户列出 8 个不同的模块，但它只循环了 6 次，这只是用户计数的数量。我想让用户拥有用户尝试过的所有模块。
这里是代码
foreach($courses as $completion) {
if(!is_null($course)) {
$coursesdata[] = $course;
}
$course = array();
$course['courseid'] = $completion->courseid;
$course['coursename'] = $completion->coursename;
$course['idnumber'] = $completion->idnumber;
$course['enrols'] = $completion->enrols;
$course['completed'] = $completion->completed;
$course['users'] = [];
if(!empty($users)) {
foreach($users as $userinfo) {
for($i=0; $i<count($users); $i++) {
$user = array();
$user['userid'] = $userinfo->userid;
$user['email'] = $userinfo->email;
$user['lastaccess'] = $userinfo->lastaccess;
$user['modules'] = array();
if(!empty($modules)) {
foreach($modules as $details) {
for($i=0; $i<count($modules); $i++) {
$module = array();
$module['module'] = $details->module;
$module['item'] = $details->item;
$module['itemidnumber'] = $details->itemidnumber;
$module['cmid'] = $details->cmid;
$module['launch'] = $details->launch;
$module['completed'] = $details->completed;
$module['timecompleted'] = $details->timecompleted;
}
if(!is_null($module)) {
$user['modules'][] = $module;
}
}
}
}
if(!is_null($user)) {
$course['users'][] = $user;
}
}
}
}
问题：如何将$modules 中的所有数据放在$users 数组下？目前它只循环 $modules 查询中的第一个元素。
我已经尝试过评论和回答中建议的方法，但这是迄今为止我得到的最接近的方法。
如有任何帮助或提示，我们将不胜感激。
提前致谢！
首先，您当前的代码容易受到 sql 注入攻击，您确实应该使用参数 Moodle Documentation。我还将模块分解为另一个查询。
$sql_2 = "SELECT DISTINCT cr.id AS courseid,
cr.fullname AS coursename,
cr.idnumber AS idnumber,
COUNT(DISTINCT ra.id) AS enrols,
COUNT(DISTINCT cc.timecompleted) AS completed
FROM {course} cr JOIN {context} ct ON ( ct.instanceid = cr.id )
LEFT JOIN {role_assignments} ra ON ( ra.contextid = ct.id ) and ra.roleid = 5
LEFT JOIN {course_completions} cc ON (cc.course = cr.id)
WHERE cr.id = :course_id GROUP BY cr.fullname, cr.id";
$sql_3 = "SELECT DISTINCT
u.id AS userid,
u.email AS email,
c.id AS courseid
FROM {user} u
JOIN {role_assignments} ra ON ra.userid = u.id
LEFT JOIN {context} ct ON ct.id = ra.contextid AND ra.roleid = 5
LEFT JOIN {course} c ON c.id = ct.instanceid AND ct.contextlevel = 50
WHERE c.id = :course_id and m.id = 18 ORDER BY u.email";
$sql_4 = "SELECT DISTINCT
u.id AS userid,
m.name AS module
FROM {user} u
JOIN {role_assignments} ra ON ra.userid = u.id
LEFT JOIN {context} ct ON ct.id = ra.contextid AND ra.roleid = 5
LEFT JOIN {course} c ON c.id = ct.instanceid AND ct.contextlevel = 50
LEFT JOIN {course_modules} cm ON cm.course = c.id
LEFT JOIN {course_modules_completion} cmc ON cmc.userid = u.id AND cmc.coursemoduleid = cm.id
LEFT JOIN {modules} m ON m.id = cm.module
LEFT JOIN {scorm} sc ON sc.id = cm.instance
WHERE c.id = :course_id and m.id = 18 ORDER BY u.email";
$courses = $DB->get_records_sql($sql_2, ["course_id" => $requestedcourseids]);
$users = $DB->get_records_sql($sql_3, ["course_id" => $requestedcourseids]);
$modules = $DB->get_records_sql($sql_4, ["course_id" => $requestedcourseids]);
$course_user_modules = [];
foreach($courses as $course){
$course["users"] = [];
foreach($users as $course_user){
if($course["courseid"]==$course_user["courseid"]){
unset($course_user["courseid"]);
$course_user["modules"] = [];
foreach($modules as $user_module){
if($user_module["userid"]==$course_user["userid"]){
unset($user_module["userid"]);
array_push($course_user["modules"], $user_module);
}
}
array_push($course["users"], $course_user);
}
}
array_push($course_user_modules, $course);
}
我在 Moodle 数据库调用 get_records_sql
中发现了问题
$modules = $DB->get_records_sql($sql_4, ["course_id" => $requestedcourseids]);
这 returns 一个由结果中的第一个字段索引的数组。这意味着在我的例子中，每个用户标识只有 returns 一组数组。
在我将 moduleid(unique value) 的 sql 查询更改为优先后，它现在按预期工作。
$sql_4 = "SELECT DISTINCT cm.id AS moduleid,
u.id AS userid,
sc.name AS item,
m.name AS module,
cm.idnumber AS itemidnumber,
sc.launch AS launch,
cmc.completionstate AS completed,
cmc.timemodified AS timecompleted
FROM {user} u
JOIN {role_assignments} ra ON ra.userid = u.id
LEFT JOIN {context} ct ON ct.id = ra.contextid AND ra.roleid = 5
LEFT JOIN {course} c ON c.id = ct.instanceid AND ct.contextlevel = 50
LEFT JOIN {course_modules} cm ON cm.course = c.id
LEFT JOIN {course_modules_completion} cmc ON cmc.userid = u.id AND cmc.coursemoduleid = cm.id
LEFT JOIN {modules} m ON m.id = cm.module
LEFT JOIN {scorm} sc ON sc.id = cm.instance
WHERE c.id = :course_id and m.id = 18 and u.id = :userid";
之前是这样的，
users:
userid: 2,
module:
moduleid: 12,
userid: 8,
module:
moduleid: 12
userid: 9,
module:
moduleid: 12,
现在我明白了，
users:
userid: 2,
module:
moduleid: 12,
moduleid: 14,
moduleid: 17,
userid: 8,
module:
moduleid: 12,
moduleid: 14,
moduleid: 17,
userid: 9,
module:
moduleid: 12,
moduleid: 14,
moduleid: 17,
这 post 帮助我解决了这个问题。
**已编辑
我将 sql 查询拆分为 3 个，现在查询如下所示。
$sql_2 = "SELECT DISTINCT cr.id AS courseid,
cr.fullname AS coursename,
cr.idnumber AS idnumber,
COUNT(DISTINCT ra.id) AS enrols,
COUNT(DISTINCT cc.timecompleted) AS completed
FROM {course} cr JOIN {context} ct ON ( ct.instanceid = cr.id )
LEFT JOIN {role_assignments} ra ON ( ra.contextid = ct.id ) and ra.roleid = 5
LEFT JOIN {course_completions} cc ON (cc.course = cr.id)
WHERE cr.id = :course_id GROUP BY cr.fullname, cr.id";
$sql_3 = "SELECT DISTINCT
u.id AS userid,
u.email AS email,
u.lastaccess,
c.id AS courseid
FROM {user} u
JOIN {role_assignments} ra ON ra.userid = u.id
LEFT JOIN {context} ct ON ct.id = ra.contextid AND ra.roleid = 5
LEFT JOIN {course} c ON c.id = ct.instanceid AND ct.contextlevel = 50
WHERE c.id = :course_id";
$sql_4 = "SELECT DISTINCT
u.id AS userid,
sc.name AS item,
m.name AS module,
cm.id AS cmid,
cm.idnumber AS itemidnumber,
sc.launch AS launch,
cmc.completionstate AS completed,
cmc.timemodified AS timecompleted
FROM {user} u
JOIN {role_assignments} ra ON ra.userid = u.id
LEFT JOIN {context} ct ON ct.id = ra.contextid AND ra.roleid = 5
LEFT JOIN {course} c ON c.id = ct.instanceid AND ct.contextlevel = 50
LEFT JOIN {course_modules} cm ON cm.course = c.id
LEFT JOIN {course_modules_completion} cmc ON cmc.userid = u.id AND cmc.coursemoduleid = cm.id
LEFT JOIN {modules} m ON m.id = cm.module
LEFT JOIN {scorm} sc ON sc.id = cm.instance
WHERE c.id = :course_id and m.id = 18";
$courses = $DB->get_records_sql($sql_2, ["course_id" => $requestedcourseids]);
$users = $DB->get_records_sql($sql_3, ["course_id" => $requestedcourseids]);
$modules = $DB->get_records_sql($sql_4, ["course_id" => $requestedcourseids]);
我在每个结果下添加了foreach和for循环得到多维数组结果得到了这样的模块结果
"course": [
{
"courseid": 4,
"coursename": "Activities",
"idnumber": "",
"enrols": 6,
"completed": 1,
"users": [
{
"userid": 3,
"email": "test1@hotmail.com",
"lastaccess": 1599379804,
"modules": [
{
"userid": 3,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": 1,
"timecompleted": 1595575023
},
{
"userid": 2,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": 0,
"timecompleted": 1593135761
},
{
"userid": 4,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": 1,
"timecompleted": 1589359945
},
{
"userid": 8,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": null,
"timecompleted": null
},
{
"userid": 7,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": null,
"timecompleted": null
}
]
},
{
"userid": 2,
"email": "test2@gmail.com",
"lastaccess": 1599635370,
"modules": [
{
"userid": 9,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": 1,
"timecompleted": 1595576987
},
{
"userid": 3,
"module": "scorm",
"item": "Vitamin",
"itemidnumber": "",
"cmid": 24,
"launch": 28,
"completed": 1,
"timecompleted": 1595575023
},,,,
如您所见，模块列表仅显示一个具有每个用户 ID 的模块。
它应该为每个用户列出 8 个不同的模块，但它只循环了 6 次，这只是用户计数的数量。我想让用户拥有用户尝试过的所有模块。
这里是代码
foreach($courses as $completion) {
if(!is_null($course)) {
$coursesdata[] = $course;
}
$course = array();
$course['courseid'] = $completion->courseid;
$course['coursename'] = $completion->coursename;
$course['idnumber'] = $completion->idnumber;
$course['enrols'] = $completion->enrols;
$course['completed'] = $completion->completed;
$course['users'] = [];
if(!empty($users)) {
foreach($users as $userinfo) {
for($i=0; $i<count($users); $i++) {
$user = array();
$user['userid'] = $userinfo->userid;
$user['email'] = $userinfo->email;
$user['lastaccess'] = $userinfo->lastaccess;
$user['modules'] = array();
if(!empty($modules)) {
foreach($modules as $details) {
for($i=0; $i<count($modules); $i++) {
$module = array();
$module['module'] = $details->module;
$module['item'] = $details->item;
$module['itemidnumber'] = $details->itemidnumber;
$module['cmid'] = $details->cmid;
$module['launch'] = $details->launch;
$module['completed'] = $details->completed;
$module['timecompleted'] = $details->timecompleted;
}
if(!is_null($module)) {
$user['modules'][] = $module;
}
}
}
}
if(!is_null($user)) {
$course['users'][] = $user;
}
}
}
}
问题：如何将$modules 中的所有数据放在$users 数组下？目前它只循环 $modules 查询中的第一个元素。
我已经尝试过评论和回答中建议的方法，但这是迄今为止我得到的最接近的方法。
如有任何帮助或提示，我们将不胜感激。
提前致谢！
首先，您当前的代码容易受到 sql 注入攻击，您确实应该使用参数 Moodle Documentation。我还将模块分解为另一个查询。
$sql_2 = "SELECT DISTINCT cr.id AS courseid,
cr.fullname AS coursename,
cr.idnumber AS idnumber,
COUNT(DISTINCT ra.id) AS enrols,
COUNT(DISTINCT cc.timecompleted) AS completed
FROM {course} cr JOIN {context} ct ON ( ct.instanceid = cr.id )
LEFT JOIN {role_assignments} ra ON ( ra.contextid = ct.id ) and ra.roleid = 5
LEFT JOIN {course_completions} cc ON (cc.course = cr.id)
WHERE cr.id = :course_id GROUP BY cr.fullname, cr.id";
$sql_3 = "SELECT DISTINCT
u.id AS userid,
u.email AS email,
c.id AS courseid
FROM {user} u
JOIN {role_assignments} ra ON ra.userid = u.id
LEFT JOIN {context} ct ON ct.id = ra.contextid AND ra.roleid = 5
LEFT JOIN {course} c ON c.id = ct.instanceid AND ct.contextlevel = 50
WHERE c.id = :course_id and m.id = 18 ORDER BY u.email";
$sql_4 = "SELECT DISTINCT
u.id AS userid,
m.name AS module
FROM {user} u
JOIN {role_assignments} ra ON ra.userid = u.id
LEFT JOIN {context} ct ON ct.id = ra.contextid AND ra.roleid = 5
LEFT JOIN {course} c ON c.id = ct.instanceid AND ct.contextlevel = 50
LEFT JOIN {course_modules} cm ON cm.course = c.id
LEFT JOIN {course_modules_completion} cmc ON cmc.userid = u.id AND cmc.coursemoduleid = cm.id
LEFT JOIN {modules} m ON m.id = cm.module
LEFT JOIN {scorm} sc ON sc.id = cm.instance
WHERE c.id = :course_id and m.id = 18 ORDER BY u.email";
$courses = $DB->get_records_sql($sql_2, ["course_id" => $requestedcourseids]);
$users = $DB->get_records_sql($sql_3, ["course_id" => $requestedcourseids]);
$modules = $DB->get_records_sql($sql_4, ["course_id" => $requestedcourseids]);
$course_user_modules = [];
foreach($courses as $course){
$course["users"] = [];
foreach($users as $course_user){
if($course["courseid"]==$course_user["courseid"]){
unset($course_user["courseid"]);
$course_user["modules"] = [];
foreach($modules as $user_module){
if($user_module["userid"]==$course_user["userid"]){
unset($user_module["userid"]);
array_push($course_user["modules"], $user_module);
}
}
array_push($course["users"], $course_user);
}
}
array_push($course_user_modules, $course);
}
我在 Moodle 数据库调用 get_records_sql
$modules = $DB->get_records_sql($sql_4, ["course_id" => $requestedcourseids]);
这 returns 一个由结果中的第一个字段索引的数组。这意味着在我的例子中，每个用户标识只有 returns 一组数组。 在我将 moduleid(unique value) 的 sql 查询更改为优先后，它现在按预期工作。
$sql_4 = "SELECT DISTINCT cm.id AS moduleid,
u.id AS userid,
sc.name AS item,
m.name AS module,
cm.idnumber AS itemidnumber,
sc.launch AS launch,
cmc.completionstate AS completed,
cmc.timemodified AS timecompleted
FROM {user} u
JOIN {role_assignments} ra ON ra.userid = u.id
LEFT JOIN {context} ct ON ct.id = ra.contextid AND ra.roleid = 5
LEFT JOIN {course} c ON c.id = ct.instanceid AND ct.contextlevel = 50
LEFT JOIN {course_modules} cm ON cm.course = c.id
LEFT JOIN {course_modules_completion} cmc ON cmc.userid = u.id AND cmc.coursemoduleid = cm.id
LEFT JOIN {modules} m ON m.id = cm.module
LEFT JOIN {scorm} sc ON sc.id = cm.instance
WHERE c.id = :course_id and m.id = 18 and u.id = :userid";
之前是这样的，
users:
userid: 2,
module:
moduleid: 12,
userid: 8,
module:
moduleid: 12
userid: 9,
module:
moduleid: 12,
现在我明白了，
users:
userid: 2,
module:
moduleid: 12,
moduleid: 14,
moduleid: 17,
userid: 8,
module:
moduleid: 12,
moduleid: 14,
moduleid: 17,
userid: 9,
module:
moduleid: 12,
moduleid: 14,
moduleid: 17,
这 post 帮助我解决了这个问题。