如何用冒号解组 xml 元素

Question

由于代码错误，我无法在 Go 中用冒号解组 xml 元素。

https://play.golang.org/p/zMm5IQSfS01

package main

import (
    "fmt"
    "encoding/xml"
)

type Obj struct {
    XMLName xml.Name `xml:"book"`
    AbcName string   `xml:"abc:name"`
}

func main() {
    a := []byte(`<book><abc:name>text</abc:name></book>`)
    obj := &Obj{}
    if err := xml.Unmarshal(a, obj); err != nil {
        panic(err)
    }
    fmt.Printf("%#v\n", obj)
}

代码输出：

&main.Obj{XMLName:xml.Name{Space:"", Local:"book"}, AbcName:""}

是否可以在 Golang 中用冒号解组 xml 元素？如果是，如何？

Answer 1

xml.Unmarshal

If the XMLName field has an associated tag of the form "name" or "namespace-URL name", the XML element must have the given name (and, optionally, name space) or else Unmarshal returns an error.

type Obj struct {
    XMLName xml.Name `xml:"book"`
    AbcName string   `xml:"abc name"`
    DefName string   `xml:"def name"`
}

func main() {
    a := []byte(`<book><abc:name>text</abc:name><def:name>some other text</def:name></book>`)
    obj := &Obj{}
    if err := xml.Unmarshal(a, obj); err != nil {
        panic(err)
    }
    fmt.Printf("%#v\n", obj)
}

如何用冒号解组 xml 元素

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