Tkinter window 在定义 window 并添加 mainloop() 后未打开

Question

我正在尝试制作具有更多功能的改进型自动答题器，例如：

按一个键保存光标位置
按键时执行
一键终止程序这是代码：

import win32api, win32com
import pyautogui
import tkinter as tk
from time import sleep
import keyboard

win = tk.Tk()
cursor = (0,0)
di = 0

e = tk.Entry()

def geti():
    di = float(e.get())


l = tk.Label(text="Info:").pack()
l1 = tk.Label(text="Press q to stop clicking").pack()
l2 = tk.Label(text="Press c to copy mouse position to execute on").pack()
l3 = tk.Label(text="Press e to start executing").pack()

dl = tk.Label(text="Delay between eack click (s)").pack()
e.pack()
b = tk.Button(text="save delay time",command=geti).pack()

def click(x, y):
    win32api.SetCursorPos((x,y))
    win32api.mouse_event(win32con.MOUSEEVENTF_LEFTDOWN,0,0)
    sleep(di)
    win32api.mouse_event(win32con.MOUSEEVENTF_LEFTUP,0,0)

while True:

    if(keyboard.is_pressed('c') == True):
        cursor = pyautogui.position()

    if(keyboard.is_pressed('q') == True):
        break
    
    if(keyboard.is_pressed('e') == True):
        click(cursor[0], cursor[1])
        
win.mainloop()

Answer 1

你的 while-loop 块 win.mainloop()。您可以将 tkinters 事件系统与绑定一起使用，而不是检查按键：

win.bind('key', callback)
# thanks to @acw1668's comment: added evt
win.bind('e', lambda evt: click(cursor[0], cursor[1]))

lambda 是必需的，因为您希望调用函数而不是结果。来自 the tkinter docs:

If you do this, Python will call the callback function before creating the widget, and pass the function’s return value to Tkinter. Tkinter then attempts to convert the return value to a string, and tells Tk to call a function with that name when the button is activated. This is probably not what you wanted.

Tkinter window 在定义 window 并添加 mainloop() 后未打开

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