计算一个或两个查询中两列的数据

Question

我的 table 中有以下不同的行：

JobID   ClientID    Date                URL
a       1           Apr 27 2020 8:21AM  http://somewebsite.com
a       1           Apr 29 2020 12:57AM http://somewebsite.com
a       1           Apr 30 2020 5:05AM  http://anotherwebsite.com
a       2           May 3 2020 6:09PM   http://anotherwebsite.com
a       3           May 20 2020 12:55AM https://thirdlink.com
b       1           Apr 30 2020 5:16AM  http://anotherwebsite.com
b       2           May 3 2020 6:09PM   http://anotherwebsite.com
b       2           May 11 2020 8:39AM  https://thirdlink.com

我正在尝试构建一个或两个会给出以下结果的查询：

每个客户每个作业的总点击次数：

JobID   ClientID    Number of Clicks
a       1           3
a       2           1
a       3           1
b       1           1
b       2           2

每个客户每个作业的唯一 URL 数量：

JobID   ClientID    Number of URLs
a       1           2
a       2           1
a       3           1
b       1           1
b       2           2

这是我尝试过的方法，但它没有正确聚合数据：

SELECT ClientID,
COUNT(ClientID) AS [Number of Clicks],
JobId
FROM [table]
GROUP BY ClientID, JobId

SELECT ClientID,
COUNT(URL) AS [Number of URLs],
JobId
FROM [table]
GROUP BY ClientID, JobId

任何有关如何实现此目的的提示，我们将不胜感激，谢谢！

Answer 1

您导致聚合和 count() 如下：

select 
    jobid, 
    clientid, 
    count(*) cnt_clicks, 
    count(distinct url) cnt_distinct_url
from mytable
group by clientid, jobid

计算一个或两个查询中两列的数据

Count data from two columns in one or two queries

sql

group-by

sql-server-2005

count

distinct