从 json 对象中提取特定数据并将它们存储在列表中

Extract specific data from json object and store them in a list

我是 json 格式世界的新手。我将 Json 信息存储在 json 对象中,我只想提取列表中的名称键值。至少我有一个用户,有时不止一个用户。使用 Java 或 Groovy.

提取
{
  "reviewers": [
    {
      "user": {
        "name": "name1.n1",
        "emailAddress": "example@example.com"
      },
      "role": "REVIEWER"
    },
    {
      "user": {
        "name": "name2.n2",
        "emailAddress": "example2@example.com"
      },
      "role": "REVIEWER"
    }
  ]
}

将 Java 与库 org.json.JSONObject 一起使用;

   JSONObject json =new JSONObject(YOUR_JSON_HERE );        
            JSONArray array = json.getJSONArray("reviewers" );
            for(int i=0;i<array.length();i++){
                JSONObject user =array.getJSONObject(i);   
                System.out.println(user.getJSONObject("user").get("name"));
            }
            
    
        }

您只需使用 Groovy:

即可获得这样的姓名列表
jason = '''{
  "reviewers": [
    {
      "user": {
        "name": "name1.n1",
        "emailAddress": "example@example.com"
      },
      "role": "REVIEWER"
    },
    {
      "user": {
        "name": "name2.n2",
        "emailAddress": "example2@example.com"
      },
      "role": "REVIEWER"
    }
  ]
}
'''


import groovy.json.JsonSlurper

def jsonslurper = new JsonSlurper()
def object = jsonslurper.parseText(jason)

List names = object.findAll { it.value instanceof List }
    .values()
    .flatten()
    .collect { it.user.name }

println names

基本 groovy+json 文档在这里:https://groovy-lang.org/json.html

import groovy.json.JsonSlurper

def json = '''{
  "reviewers": [
    {
      "user": {
        "name": "name1.n1",
        "emailAddress": "example@example.com"
      },
      "role": "REVIEWER"
    },
    {
      "user": {
        "name": "name2.n2",
        "emailAddress": "example2@example.com"
      },
      "role": "REVIEWER"
    }
  ]
}
'''

def obj = new JsonSlurper().parseText(json)

println obj.reviewers.collect{ it.user.name } // v1
println obj.reviewers*.user.name              // the same as above but shorter