Python:如何在 pygame 中使绘制的元素对齐网格
Python: How to make drawn elements snap to grid in pygame
我正在试验 Pathfinding 项目,但在创建工作 GUI 时卡住了。我正在使用 pygame 并且已经创建了一个网格和一个特征,当您按下(或持续按下)鼠标按钮时它会绘制立方体。然而,这些立方体只是随您点击而移动,不会捕捉到网格。我考虑过以某种方式使用模数,但我似乎无法让它工作。请在下面找到代码。立方体 class 是我用来在屏幕上绘制的正方形。此外,drawgrid()
函数是我设置网格的方式。我很想在这方面得到一些帮助,因为我已经被困在这个障碍上三天了。
class Cube:
def update(self):
self.cx, self.cy = pygame.mouse.get_pos()
self.square = pygame.Rect(self.cx, self.cy, 20, 20)
def draw(self):
click = pygame.mouse.get_pressed()
if click[0]: # evaluate left button
pygame.draw.rect(screen, (255, 255, 255), self.square)
其他drawgrid()
功能:
def drawgrid(w, rows, surface):
sizebtwn = w // rows # Distance between Lines
x = 0
y = 0
for i in range(rows):
x = x + sizebtwn
y = y + sizebtwn
pygame.draw.line(surface, (255, 255, 255), (x, 0), (x, w))
pygame.draw.line(surface, (255, 255, 255), (0, y), (w, y))
您必须将位置与网格大小对齐。使用底除运算符(//
)将坐标除以单元格大小并计算网格中的积分索引:
x, y = pygame.mouse.get_pos()
ix = x // sizebtwn
iy = y // sizebtwn
将结果乘以单元格的大小来计算坐标:
self.cx, self.cy = ix * sizebtwn, iy * sizebtwn
最小示例:
import pygame
pygame.init()
screen = pygame.display.set_mode((200, 200))
clock = pygame.time.Clock()
def drawgrid(w, rows, surface):
sizebtwn = w // rows
for i in range(0, w, sizebtwn):
x, y = i, i
pygame.draw.line(surface, (255, 255, 255), (x, 0), (x, w))
pygame.draw.line(surface, (255, 255, 255), (0, y), (w, y))
class Cube:
def update(self, sizebtwn):
x, y = pygame.mouse.get_pos()
ix = x // sizebtwn
iy = y // sizebtwn
self.cx, self.cy = ix * sizebtwn, iy * sizebtwn
self.square = pygame.Rect(self.cx, self.cy, sizebtwn, sizebtwn)
def draw(self, surface):
click = pygame.mouse.get_pressed()
if click[0]:
pygame.draw.rect(surface, (255, 255, 255), self.square)
cube = Cube()
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
cube.update(screen.get_width() // 10)
screen.fill(0)
drawgrid(screen.get_width(), 10, screen)
cube.draw(screen)
pygame.display.flip()
我正在试验 Pathfinding 项目,但在创建工作 GUI 时卡住了。我正在使用 pygame 并且已经创建了一个网格和一个特征,当您按下(或持续按下)鼠标按钮时它会绘制立方体。然而,这些立方体只是随您点击而移动,不会捕捉到网格。我考虑过以某种方式使用模数,但我似乎无法让它工作。请在下面找到代码。立方体 class 是我用来在屏幕上绘制的正方形。此外,drawgrid()
函数是我设置网格的方式。我很想在这方面得到一些帮助,因为我已经被困在这个障碍上三天了。
class Cube:
def update(self):
self.cx, self.cy = pygame.mouse.get_pos()
self.square = pygame.Rect(self.cx, self.cy, 20, 20)
def draw(self):
click = pygame.mouse.get_pressed()
if click[0]: # evaluate left button
pygame.draw.rect(screen, (255, 255, 255), self.square)
其他drawgrid()
功能:
def drawgrid(w, rows, surface):
sizebtwn = w // rows # Distance between Lines
x = 0
y = 0
for i in range(rows):
x = x + sizebtwn
y = y + sizebtwn
pygame.draw.line(surface, (255, 255, 255), (x, 0), (x, w))
pygame.draw.line(surface, (255, 255, 255), (0, y), (w, y))
您必须将位置与网格大小对齐。使用底除运算符(//
)将坐标除以单元格大小并计算网格中的积分索引:
x, y = pygame.mouse.get_pos()
ix = x // sizebtwn
iy = y // sizebtwn
将结果乘以单元格的大小来计算坐标:
self.cx, self.cy = ix * sizebtwn, iy * sizebtwn
最小示例:
import pygame
pygame.init()
screen = pygame.display.set_mode((200, 200))
clock = pygame.time.Clock()
def drawgrid(w, rows, surface):
sizebtwn = w // rows
for i in range(0, w, sizebtwn):
x, y = i, i
pygame.draw.line(surface, (255, 255, 255), (x, 0), (x, w))
pygame.draw.line(surface, (255, 255, 255), (0, y), (w, y))
class Cube:
def update(self, sizebtwn):
x, y = pygame.mouse.get_pos()
ix = x // sizebtwn
iy = y // sizebtwn
self.cx, self.cy = ix * sizebtwn, iy * sizebtwn
self.square = pygame.Rect(self.cx, self.cy, sizebtwn, sizebtwn)
def draw(self, surface):
click = pygame.mouse.get_pressed()
if click[0]:
pygame.draw.rect(surface, (255, 255, 255), self.square)
cube = Cube()
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
cube.update(screen.get_width() // 10)
screen.fill(0)
drawgrid(screen.get_width(), 10, screen)
cube.draw(screen)
pygame.display.flip()