如何将字符串值转换为函数中的自定义类型

Question

我写了一个角色检查函数：

...
role = "roles/cloudkms.publicKeyViewer"
func checkRole(key, serviceAccount, role string) bool {
...
return policy.HasRole(serviceAccount, role)
}

然后我收到错误“不能将角色（类型字符串）用作类型”cloud.google。com/go/iam”。policy.HasRole.[=13= 的参数中的 RoleName ]

将角色值转换为自定义类型的正确方法是什么？

The library:

// A RoleName is a name representing a collection of permissions.
type RoleName string

// Common role names.
const (
    Owner  RoleName = "roles/owner"
    Editor RoleName = "roles/editor"
    Viewer RoleName = "roles/viewer"
)

const (
    // AllUsers is a special member that denotes all users, even unauthenticated ones.
    AllUsers = "allUsers"

    // AllAuthenticatedUsers is a special member that denotes all authenticated users.
    AllAuthenticatedUsers = "allAuthenticatedUsers"
)


// HasRole reports whether member has role r.
func (p *Policy) HasRole(member string, r RoleName) bool {
    return memberIndex(member, p.binding(r)) >= 0
}

Answer 1

您可以使用如下类型转换：

return policy.HasRole(serviceAccount, iam.RoleName(role))

或者通过将角色声明为 iam.RoleName

来更简单

func checkRole(key, serviceAccount, role iam.RoleName) bool {
...
   return policy.HasRole(serviceAccount, role)
}

如何将字符串值转换为函数中的自定义类型

How to convert string value to custom type in function

go

google-iam

google-cloud-iam