检查最近 10 根蜡烛期间是否发生交叉

Question

我正在研究一种策略，当我在当前蜡烛收盘时收到信号时，要求我及时检查是否有特定的交叉几根蜡烛。

现在我基本上为每根蜡烛创建 10 个变量，因为我想检查 10 根蜡烛并查看是否发生了交叉（任何类型的交叉都适用于此示例）。

这行得通，但会导致一些混乱和冗长的代码，所以我想知道我是否可以以某种方式创建一个“一个班轮”解决方案来检查整个期间的情况？

Answer 1

这可能有帮助

//@version=4
study("Sma cross during last n candles", overlay=true)

sma20 = sma(close, 20)
sma50 = sma(close, 50)

plot(sma20)
plot(sma50)

cross = cross(sma20, sma50)

// Highligh cross on the chart
bgcolor(cross ? color.red : na)

// Function looking for a happened condition during lookback period
f_somethingHappened(_cond, _lookback) =>
    bool _crossed = false
    for i = 1 to _lookback
        if _cond[i]
            _crossed := true
    _crossed

// The function could be called multiple times on different conditions, that should reduce the code
crossed10 = f_somethingHappened(cross, 10)

// Highligh background if cross happened during last 10 bars
bgcolor(crossed10 ? color.green : na)

Answer 2

或者你可以只使用这个条件：

if ta.valuewhen(crossover(sma20, sma50), bar_index, 0) <= 10

//do whatever it is you want to do after the if condition

检查最近 10 根蜡烛期间是否发生交叉

Check if crossover occurred in the period of last 10 candles

pine-script

pine-script-v4