如何使用 python 访问在其他函数中创建的 kwargs?

How to access kwargs created in an other function using python?

我正在研究具有很多功能的大型有限元分析代码。为了在不同函数之间传递变量,我使用了 python 的 kwargs。我选择这个主要是因为我可以用很多不同的方式调用函数,创造了很大的灵活性。

但是现在我正在处理一个问题。从一个主函数我使用 kwargs 调用另一个函数。第二个函数然后处理输入并添加新的 kwargs。问题是在第一个函数中无法访问在该函数中创建的新 kwargs。有没有 pythonic 方法可以做到这一点?我创建了以下代码作为示例:

# Create main function
def main(**kwargs):
    # Add a key word argument
    kwargs["textMain"] = "text added in main"

    # Call a function with existing kwargs and a new one
    functionA(textNew = "text added in new" ,**kwargs)

    # Test what is in kwargs after subfunction is called
    print("\nTest kwargs after subfunction is called:")

    if "textMain" in kwargs:
        print(kwargs["textMain"])

    if "textNew" in kwargs:
        print(kwargs["textNew"])

    if "textA" in kwargs:
        print(kwargs["textA"])

def functionA(**kwargs):

    # Test kwargs before adding kwargs in subfunction
    print("\nTest kwargs in subfunction before adding:")

    if "textMain" in kwargs:
        print(kwargs["textMain"])

    if "textNew" in kwargs:
        print(kwargs["textNew"])

    if "textA" in kwargs:
        print(kwargs["textA"])

    # Add kwargs
    kwargs["textA"] = "text added in sub A"

    # and test kwargs again
    print("\nTest kwargs in subfunction after adding:")
    if "textMain" in kwargs:
        print(kwargs["textMain"])

    if "textNew" in kwargs:
        print(kwargs["textNew"])

    if "textA" in kwargs:
        print(kwargs["textA"])

if __name__ == "__main__":
    main()

这会产生以下输出:

#Test kwargs in subfunction before adding:
#text added in main
#text added in new

#Test kwargs in subfunction after adding:
#text added in main
#text added in new
#text added in sub A

#Test kwargs after subfunction is called:
#text added in main

我的首选输出是:

#Test kwargs in subfunction before adding:
#text added in main
#text added in new

#Test kwargs in subfunction after adding:
#text added in main
#text added in new
#text added in sub A

#Test kwargs after subfunction is called:
#text added in main
#text added in new
#text added in sub A

如果有人能解决我的问题,那将是非常有帮助的。提前致谢!

当您在调用表达式中使用 **kwargs 语法时,Python 会扩展字典并传入单独的参数。函数签名中的相同语法然后告诉 Python 在该函数中创建一个 new 字典以捕获关键字参数。

换句话说,main() 中的 kwargsfunctionA() 中的字典不同。

要么传入实际字典(不使用 **kwargs 语法),要么有 functionA() return 一个 new 字典。

kwargs 作为单个参数传入,您可以更改 functionA() 中的字典并查看 main() 中反映的更改,因为它们现在共享对同一字典的引用:

def main(**kwargs):
    functionA(kwargs, textNew="text added in new")
    # ... etc ...


def functionA(mapping, **kwargs):
    # do something with mapping, it is the same dictionary as kwargs in main

functionA() 返回更新后的 kwargs 字典需要您将新对象分配回 main() 中的 kwargs:

def main(**kwargs):
    kwargs = functionA(textNew="text added in new", **kwargs)
    # ... etc ...

def functionA(**kwargs):
    # ...
    return kwargs