在非连续大写字母上拆分字符串

Question

我正在尝试按大写字母拆分字符串，但我不想拆分两个连续的大写字母。

所以现在我正在这样做：

my_string == "TTestStringAA"
re.findall('[a-zA-Z][^A-Z]*', my_string)
>>> ['T', 'Test', 'String', 'A', 'A']

但我正在寻找的输出是：

>>> ['TTest', 'String', 'AA']

这个问题有干净简单的解决方案吗？

谢谢！

Answer 1

我认为[A-Z]+[a-z]*符合您的要求：

>>> re.findall(r'[A-Z]+[a-z]*', my_string)
['TTest', 'String', 'AA']

Answer 2

以下正则表达式将 return 正确的结果。

[a-z]*[A-Z]+[a-z]*|[a-z]+$

测试用例：

tests = ['a', 'A', 'aa', 'Aa' 'AaAaAAAaAa', 'aTTestStringAA']
regex = re.compile(r'[a-z]*[A-Z]+[a-z]*|[a-z]+$')
for test in tests:
    print('{} => {}'.format(test, re.findall(regex, test)))

Answer 3

将re.split与

结合使用

(?<=[a-z])(?=[A-Z])

参见 proof。

说明

--------------------------------------------------------------------------------
  (?<=                     look behind to see if there is:
--------------------------------------------------------------------------------
    [a-z]                    any character of: 'a' to 'z'
--------------------------------------------------------------------------------
  )                        end of look-behind
--------------------------------------------------------------------------------
  (?=                      look ahead to see if there is:
--------------------------------------------------------------------------------
    [A-Z]                    any character of: 'A' to 'Z'
--------------------------------------------------------------------------------
  )                        end of look-ahead

Python code:

import re
pattern = r"(?<=[a-z])(?=[A-Z])"
test = "TTestStringAA"
print(re.split(pattern, test))

结果：

['TTest', 'String', 'AA']

在非连续大写字母上拆分字符串

Split string on non consecutive capital letters

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