按回车键后无法更改页面
I can't get my page to change after I hit the enter key
我一直在一个网站上工作,但由于某种原因,当我点击进入时它停留在同一页面上。但是,当我单击我在页面本身上添加的按钮时,它就起作用了。我想做的是在验证密码后从我的登录页面 index.html 转到我的主页 home.html。有什么想法吗?
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="/popup.css?Version=1.1">
</head>
<body>
<div id="box">
<form id="myform-search" method="post" autocomplete="off">
<h1>Enter Password</h1>
<p>
<input type="password" value="" placeholder="Enter Password" id="p" class="password">
<button class="unmask" type="button" onclick="toggle()"></button>
<button class="enter" type="button" onclick="done()">Enter</button>
</p>
</form>
</div>
<div id="wrong">
<p>Sorry, but the password you entered is incorrect!</p>
</div>
<!--Javascript to show password Box-->
<script>
//Verifies password
function done() {
document.getElementById("box").style.display = "none";
var password = document.getElementById("p").value;
if (password == "12345") {
location.replace("http://apr.great-site.net/Home/home.html");
} else {
document.getElementById("wrong").style.display = "block";
}
};
function toggle() {
var x = document.getElementById("p");
if (x.type === "password") {
x.type = "text";
} else {
x.type = "password";
}
}
</script>
</body>
</html>
```````````````````````````````````````````
试试这个:
<form onSubmit="done()">
<p>
<input type="password" value="" placeholder="Enter Password" id="p" class="password">
<button class="unmask" type="button" onclick="toggle()"></button>
<button type="submit" class="enter">Enter</button>
</p>
</form>
// Verifies password
function done() {
document.getElementById("box").style.display = "none";
var password = document.getElementById("p").value;
if (password == "12345") {
// returning true will submit the form
return true;
} else {
document.getElementById("wrong").style.display = "block";
// returning false will prevent submiting the form
return false;
}
};
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="/popup.css?Version=1.1">
</head>
<body>
<div id="box">
<form id="myform-search" method="post" action="validationUrlHere" autocomplete="off" onsubmit="return done();">
<h1>Enter Password</h1>
<p>
<input type="password" value="" placeholder="Enter Password" id="p" class="password">
<!-- Commented this button as it is not needed in the context of the solution -->
<!--<button class="unmask" type="button" onclick="toggle()">something</button>-->
<!-- HERE is the interesting part : -->
<!-- Clicking the "Enter" button has same effect as -->
<!-- hitting the default submit button or pressing the Enter button on your -->
<!-- keyboard. Your cursor focus must be inside one of the form's elements, -->
<!-- preferably in the password input field -->
<button class="enter" type="button" onclick="done()">Enter</button>
<input type="submit" value="Real Submit" />
</p>
</form>
</div>
<div id="wrong" style="display: none;">
<p>Sorry, but the password you entered is incorrect!</p>
</div>
</body>
</html>
看看这个片段,从中获取你需要的东西。说实话,不清楚你在寻找什么......希望它能帮助你了解一些基础知识:-)
如果您希望在您按下回车键时调用 done() 函数,您应该在您的表单上为 Enter 添加一个事件侦听器。 (请记住,您打开了 2 个表单标签)
document.getElementById('myform-search').addEventListener('keyup', function(e) {
if(e.key=='Enter') {
done()
}
}
我一直在一个网站上工作,但由于某种原因,当我点击进入时它停留在同一页面上。但是,当我单击我在页面本身上添加的按钮时,它就起作用了。我想做的是在验证密码后从我的登录页面 index.html 转到我的主页 home.html。有什么想法吗?
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="/popup.css?Version=1.1">
</head>
<body>
<div id="box">
<form id="myform-search" method="post" autocomplete="off">
<h1>Enter Password</h1>
<p>
<input type="password" value="" placeholder="Enter Password" id="p" class="password">
<button class="unmask" type="button" onclick="toggle()"></button>
<button class="enter" type="button" onclick="done()">Enter</button>
</p>
</form>
</div>
<div id="wrong">
<p>Sorry, but the password you entered is incorrect!</p>
</div>
<!--Javascript to show password Box-->
<script>
//Verifies password
function done() {
document.getElementById("box").style.display = "none";
var password = document.getElementById("p").value;
if (password == "12345") {
location.replace("http://apr.great-site.net/Home/home.html");
} else {
document.getElementById("wrong").style.display = "block";
}
};
function toggle() {
var x = document.getElementById("p");
if (x.type === "password") {
x.type = "text";
} else {
x.type = "password";
}
}
</script>
</body>
</html>
```````````````````````````````````````````
试试这个:
<form onSubmit="done()">
<p>
<input type="password" value="" placeholder="Enter Password" id="p" class="password">
<button class="unmask" type="button" onclick="toggle()"></button>
<button type="submit" class="enter">Enter</button>
</p>
</form>
// Verifies password
function done() {
document.getElementById("box").style.display = "none";
var password = document.getElementById("p").value;
if (password == "12345") {
// returning true will submit the form
return true;
} else {
document.getElementById("wrong").style.display = "block";
// returning false will prevent submiting the form
return false;
}
};
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="/popup.css?Version=1.1">
</head>
<body>
<div id="box">
<form id="myform-search" method="post" action="validationUrlHere" autocomplete="off" onsubmit="return done();">
<h1>Enter Password</h1>
<p>
<input type="password" value="" placeholder="Enter Password" id="p" class="password">
<!-- Commented this button as it is not needed in the context of the solution -->
<!--<button class="unmask" type="button" onclick="toggle()">something</button>-->
<!-- HERE is the interesting part : -->
<!-- Clicking the "Enter" button has same effect as -->
<!-- hitting the default submit button or pressing the Enter button on your -->
<!-- keyboard. Your cursor focus must be inside one of the form's elements, -->
<!-- preferably in the password input field -->
<button class="enter" type="button" onclick="done()">Enter</button>
<input type="submit" value="Real Submit" />
</p>
</form>
</div>
<div id="wrong" style="display: none;">
<p>Sorry, but the password you entered is incorrect!</p>
</div>
</body>
</html>
看看这个片段,从中获取你需要的东西。说实话,不清楚你在寻找什么......希望它能帮助你了解一些基础知识:-)
如果您希望在您按下回车键时调用 done() 函数,您应该在您的表单上为 Enter 添加一个事件侦听器。 (请记住,您打开了 2 个表单标签)
document.getElementById('myform-search').addEventListener('keyup', function(e) {
if(e.key=='Enter') {
done()
}
}