如何在仅捕获句号和句号后的空格的同时将文本拆分为单词？

Question

我想拆分这段文字，

"Tom works. Tom is a student. Bob is a student."

进入这个，

["Tom", "works", ".", " ", "Tom", "is", "a", "student", ".", " ", "Bob", "is", "a", "student", "."]

我试过 text.split(/(\.)(\s)/) 但我不确定如何在不捕获空间的情况下添加空间分割。

Answer 1

您可以在 non-captured space 秒、或捕获周期 and 可选地捕获 space，然后过滤掉空匹配：

console.log(
  "Tom works. Tom is a student. Bob is a student."
    .split(/ |(\.)(\s)?/)
    .filter(Boolean)
);

另一种方法，使用 .match 而不是 split，并使用 lookbehind：

console.log(
  "Tom works. Tom is a student. Bob is a student."
    .match(/[^\s.]+|\.|(?<=\.) /g)
);

How to split text into words while only capturing full stops and spaces that come after full stops?