React:将多个过滤器应用于数组

React: apply multiple filters to array

我从 React 开始,我有一个名为 arrayToFilter 的对象数组,我想应用多个过滤器,理想情况下,当用户更改过滤器 select 选项时,所有过滤器都应应用于该数组,并且结果返回到 filteredResults 数组中显示,我已经有了每个过滤器函数及其常量,但我不知道如何一个接一个地应用所有过滤器...

这是我的代码:

    const [ arrayToFilter, setArrayToFilter ] = useState([ /*array of objects to apply filters to*/ ]);
    const [ filteredResults, setFilteredResults] = useState([ /*array of filtered objects*/ ]);
    const [ categoryOptions, setCategoryOptions ] = useState([ 1,2,3 ]);
    const [ selectedCategoryOptions, setSelectedCategoryOptions ] = useState([ ]);
    const [ searchName, setSearchName ] = useState('');
    const [ hideVenuesWithoutDiscounts, setHideVenuesWithoutDiscounts ] = useState(true);

    const filterHideVenuesWithoutDiscounts = () => 
    {
        if(hideVenuesWithoutDiscounts)
        {
            return arrayToFilter.filter(item => item.discounts.length > 0);
        }
        else
        {
            return arrayToFilter;
        }   
    };

    const filterSelectedCategoryOptions = () => 
    {
        return arrayToFilter.filter(item => item.category_id.includes(selectedCategoryOptions));
    };

    const filtersearchName = () => 
    {
        return arrayToFilter.filter(item =>  item.name.toLowerCase().indexOf(searchTerm.toLowerCase()) != -1);
    };

    useEffect(() => 
    {
        //Filter options updated so apply all filters here
    },
    [searchName, hideVenuesWithoutDiscounts, selectedCategoryOptions]);

注意 useEffect,afaik 这就像在 vue 中观察 属性,我想在过滤器输入更改时触发所有过滤器

您可以在数组中将多个过滤器链接在一起。

arrayToFilter
.filter(item => item.category_id.includes(selectedCategoryOptions))
.filter(item => item.discounts.length > 0)
.filter((item) => item.name.toLowerCase().indexOf(searchTerm.toLowerCase()) != -1)

很简单,将过滤后的数组作为参数传递给过滤函数,过滤后的数组就可以过滤了。

例如:

const filterHideVenuesWithoutDiscounts = (array) => {
    if (hideVenuesWithoutDiscounts) {
        return array.filter((item) => item.discounts.length > 0);
    } else {
        return array;
    }
};

const filterSelectedCategoryOptions = (array) => {
    return array.filter((item) => item.category_id.includes(selectedCategoryOptions));
};

const filtersearchName = (array) => {
    return array.filter((item) => item.name.toLowerCase().indexOf(searchTerm.toLowerCase()) != -1);
};

useEffect(() => {
    //Filter options updated so apply all filters here
    let result = arrayToFilter;
    result = filterHideVenuesWithoutDiscounts(result);
    result = filterSelectedCategoryOptions(result);
    result = filtersearchName(result);
    setArrayToFilter(result);
}, [searchName, hideVenuesWithoutDiscounts, selectedCategoryOptions]);

我可以建议另一种方法,使用 Array.reduce,因为链接 Array.filters 每次都会遍历整个数组,如果数组很大,这可能会占用大量资源。

示例:

const filterMethods = [
  (item => item.category_id.includes(selectedCategoryOptions)),
  (item => item.discounts.length > 0),
  ((item) => item.name.toLowerCase().indexOf(searchTerm.toLowerCase()) != -1)
]

const filteredArray = arrayToFilter.reduce((accumulator, currentItem) => {
  for (let i = 0; i < filterMethods.length; i++) {
    if (!filterMethods[i](currentItem)) {
      return accumulator
    }
  }
  return [...accumulator, currentItem]
}, [])

编辑: 睡了一会儿后,我注意到您实际上可以使用与 reduce 类似的方式使用 Array.filter,而无需多次遍历数组。

const filterMethods = [
  (item => item.category_id.includes(selectedCategoryOptions)),
  (item => item.discounts.length > 0),
  ((item) => item.name.toLowerCase().indexOf(searchTerm.toLowerCase()) != -1)
]

const filteredArray = arrayToFilter.filter((item) => {
  for (let i = 0; i < filterMethods.length; i++) {
    if (!filterMethods[i](item)) {
      return false
    }
  }
  return true
})