如何在左键单击时显示 QMenu

Question

QMenu 出现在 QLineEdit right-click 上。问题：如何修改此代码以在 left-click 上也显示菜单？

from PyQt4.QtCore import *
from PyQt4.QtGui import *
import sys

class MyWindow(QWidget):
    def __init__(self, *args):
        QWidget.__init__(self, *args)

    def actionFunct(self, argBool):
        print 'actionFunct()', argBool

    def buildGUI(self):
        self.line=QLineEdit(self)
        self.line.setText('My Line Edit')      

        self.menu=QMenu(self.line)

        self.line.installEventFilter(self)
        self.menu.installEventFilter(self)

        for i in range(3):
            actn=QAction('Action 0%s'%i, self.menu, checkable=True)
            actn.triggered.connect(self.actionFunct)
            self.menu.addAction(actn)

        self.line.setContextMenuPolicy(Qt.CustomContextMenu)
        self.line.connect(self.line, SIGNAL("customContextMenuRequested(QPoint)" ), self.lineClicked)

        layout=QVBoxLayout(self)
        layout.addWidget(self.line)
        self.setLayout(layout)

    def lineClicked(self, QPos):
        print 'lineClicked', QPos
        parentPosition = self.line.mapToGlobal(QPoint(0, 0))        
        menuPosition = parentPosition + QPos

        self.menu.move(menuPosition)
        self.menu.show() 

if __name__ == "__main__":
    app = QApplication(sys.argv)
    w = MyWindow()
    w.buildGUI()
    w.show()
    sys.exit(app.exec_())

Answer 1

您需要在 Window class 到 filter/handle 事件上定义一个 eventFilter 方法。

def eventFilter(self, obj, event):
    if obj == self.line and isinstance(event, QMouseEvent) and event.buttons() & Qt.LeftButton:
        self.lineClicked(event.pos())
        return True
    return False

Answer 2

解决方案 # 1（感谢 Brendan Abel）。

使用installEventFilter()方法通过easy-to-be-customizedeventFilter()方法路由所有lineedit事件：

self.line.installEventFilter(self)

现在所有事件 self.line 触发器都将经历 eventFilter。在那里使用接收到的 event 对象我们查询位置使用：

event.pos()

我们将其作为参数发送给 leftClicked() 方法（在 lineeidit 的 right-click 上调用了相同的方法）。来自 PyQt4.QtCore 导入 * 从 PyQt4.QtGui 导入 * 导入系统

class MyWindow(QWidget):
    def __init__(self, *args):
        QWidget.__init__(self, *args)

    def actionFunct(self, argBool):
        print 'actionFunct()', argBool

    def buildGUI(self):
        self.line=QLineEdit(self)
        self.line.setText('My Line Edit')      
        self.line.installEventFilter(self)

        self.menu=QMenu(self.line)

        for i in range(3):
            actn=QAction('Action 0%s'%i, self.menu, checkable=True)
            actn.triggered.connect(self.actionFunct)
            self.menu.addAction(actn)

        self.line.setContextMenuPolicy(Qt.CustomContextMenu)
        self.line.connect(self.line, SIGNAL("customContextMenuRequested(QPoint)" ), self.leftClicked)

        self.line.cursorPositionChanged.connect(self.leftClicked)

        layout=QVBoxLayout(self)
        layout.addWidget(self.line)
        self.setLayout(layout)


    def eventFilter(self, widget, event):
        print 'eventFilter', widget, event
        if widget == self.line and isinstance(event, QMouseEvent) and event.buttons() & Qt.LeftButton:
            self.leftClicked(event.pos())
            return True
        return False

    def leftClicked(self, QPos):
        print 'leftClicked', QPos
        parentPosition = self.line.mapToGlobal(QPoint(0, 0))        
        menuPosition = parentPosition + QPos

        self.menu.move(menuPosition)
        self.menu.show() 

if __name__ == "__main__":
    app = QApplication(sys.argv)
    w = MyWindow()
    w.buildGUI()
    w.show()
    sys.exit(app.exec_())

解决方案 # 2

首先将QLineEdit的easiest-to-triggercursorPositionChanged信号连接到一个方法。在 left-click 上调用此方法时，使用 Qt 的 QCursor.pos():

查询当前鼠标光标位置

current_mouse_cursor=QCursor.pos()

其中 returns 类似于：

QtCore.QPoint(852, 595)

最后将菜单移动到查询到的鼠标光标位置并显示：

    self.menu.move(current_mouse_cursor)
    self.menu.show()

下面发布了一个工作代码：

from PyQt4.QtCore import *
from PyQt4.QtGui import *
import sys

class MyWindow(QWidget):
    def __init__(self, *args):
        QWidget.__init__(self, *args)

    def actionFunct(self, argBool):
        print 'actionFunct()', argBool

    def buildGUI(self):
        self.line=QLineEdit(self)
        self.line.setText('My Line Edit')      

        self.menu=QMenu(self.line)

        for i in range(3):

            actn=QAction('Action 0%s'%i, self.menu, checkable=True)
            actn.triggered.connect(self.actionFunct)
            self.menu.addAction(actn)

        self.line.setContextMenuPolicy(Qt.CustomContextMenu)
        self.line.connect(self.line, SIGNAL("customContextMenuRequested(QPoint)" ), self.rightClicked)

        self.line.cursorPositionChanged.connect(self.leftClicked)

        layout=QVBoxLayout(self)
        layout.addWidget(self.line)
        self.setLayout(layout)


    def leftClicked(self, arg):
        print 'leftClicked', arg, QCursor.pos()
        self.menu.move(QCursor.pos())
        self.menu.show() 

    def rightClicked(self, QPos):
        print 'rightClicked', QPos
        parentPosition = self.line.mapToGlobal(QPoint(0, 0))        
        menuPosition = parentPosition + QPos

        self.menu.move(menuPosition)
        self.menu.show() 

if __name__ == "__main__":
    app = QApplication(sys.argv)
    w = MyWindow()
    w.buildGUI()
    w.show()
    sys.exit(app.exec_())

如何在左键单击时显示 QMenu

How to show QMenu on left click

python

qt

pyqt

qlineedit

qmenu

解决方案 # 1（感谢 Brendan Abel）。

解决方案 # 2