Laravel- 如何从集合中删除密钥?
Laravel- How to Remove a key from collection?
我有如下数据:
[
{
"id": "3",
"title": "Boruto's Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "4",
"title": "Misuki's Photo",
"is_lottery": 0,
"price": 20
}
]
我想过滤 is_lottery == false 从此集合中删除价格键。输出为:
[
{
"id": "3",
"title": "Boruto's Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "4",
"title": "Misuki's Photo",
"is_lottery": 0,
}
]
你可以做到
$json = '[
{
"id": "3",
"title": "Boruto\'s Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "3",
"title": "Misuki\'s Photo",
"is_lottery": 0,
"price": 20
}
]';
$filtered = collect(json_decode($json, true))->map(function ($array) {
if (!$array['is_lottery']) {
unset($array['price']);
}
return $array;
});
对于原生 PHP 你可以做到
$data = json_decode($json, true);
foreach ($data as $index => $array) {
if (!$array['is_lottery']) {
unset($array['price']);
}
$data[$index] = $array;
}
您可以将名为 $newCollection 的新变量声明为最终集合。使用 foreach()
迭代您的集合,然后使用 unset()
从集合中删除 is_lottery
,然后将其推送到 $newCollection,这是您如何使用 foreach
删除它的示例:
$newCollection = [];
foreach ($photos as $key => $value) {
if ($value["is_lottery"] == 0) {
unset($value["price"]);
}
array_push($newCollection,$value);
}
或者您可以尝试使用 forget
将其从该参考文献的集合(未测试)中删除:
$json = [
{
"id": "3",
"title": "Boruto's Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "4",
"title": "Misuki's Photo",
"is_lottery": 0,
"price": 20
}
];
$filtered = collect(json_decode($json))->map(function($value, $key) {
if (!$value['is_lottery']) {
Arr::except($value, 'price');
}
return $value;
});
我有如下数据:
[
{
"id": "3",
"title": "Boruto's Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "4",
"title": "Misuki's Photo",
"is_lottery": 0,
"price": 20
}
]
我想过滤 is_lottery == false 从此集合中删除价格键。输出为:
[
{
"id": "3",
"title": "Boruto's Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "4",
"title": "Misuki's Photo",
"is_lottery": 0,
}
]
你可以做到
$json = '[
{
"id": "3",
"title": "Boruto\'s Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "3",
"title": "Misuki\'s Photo",
"is_lottery": 0,
"price": 20
}
]';
$filtered = collect(json_decode($json, true))->map(function ($array) {
if (!$array['is_lottery']) {
unset($array['price']);
}
return $array;
});
对于原生 PHP 你可以做到
$data = json_decode($json, true);
foreach ($data as $index => $array) {
if (!$array['is_lottery']) {
unset($array['price']);
}
$data[$index] = $array;
}
您可以将名为 $newCollection 的新变量声明为最终集合。使用 foreach()
迭代您的集合,然后使用 unset()
从集合中删除 is_lottery
,然后将其推送到 $newCollection,这是您如何使用 foreach
删除它的示例:
$newCollection = [];
foreach ($photos as $key => $value) {
if ($value["is_lottery"] == 0) {
unset($value["price"]);
}
array_push($newCollection,$value);
}
或者您可以尝试使用 forget
将其从该参考文献的集合(未测试)中删除:
$json = [
{
"id": "3",
"title": "Boruto's Photo",
"is_lottery": 1,
"price": 10
},
{
"id": "4",
"title": "Misuki's Photo",
"is_lottery": 0,
"price": 20
}
];
$filtered = collect(json_decode($json))->map(function($value, $key) {
if (!$value['is_lottery']) {
Arr::except($value, 'price');
}
return $value;
});