获得满足条件的更深层元素

Question

    "address_components": [
    {
        "long_name": "8",
        "short_name": "8",
        "types": [
            "street_number"
        ]
    },
    {
        "long_name": "Promenade",
        "short_name": "Promenade",
        "types": [
            "route"
        ]
    },
    {
        "long_name": "Cheltenham",
        "short_name": "Cheltenham",
        "types": [
            "postal_town"
        ]
    },
    {
        "long_name": "Gloucestershire",
        "short_name": "Gloucestershire",
        "types": [
            "administrative_area_level_2",
            "political"
        ]
    },
    {
        "long_name": "England",
        "short_name": "England",
        "types": [
            "administrative_area_level_1",
            "political"
        ]
    },
    {
        "long_name": "United Kingdom",
        "short_name": "GB",
        "types": [
            "country",
            "political"
        ]
    },
    {
        "long_name": "GL50 1LR",
        "short_name": "GL50 1LR",
        "types": [
            "postal_code"
        ]
    }
],

需要获取postal_code值，即types=postal_code的long_name的值。在 api 结果中，类型本身似乎是一个数组。循环查找是一个不好的方法。也 array_search 也不起作用。谁能帮帮我

Answer 1

只需遍历数组并找到带有邮政编码的项目：

foreach ($arr["address_components"] as $item) {
    if (in_array("postal_code", $item["types"])) {
        echo $item["long_name"];
    }
}

我会把错误处理留给你。

Answer 2

您可以使用 array_filter 来迭代数组而无需循环：



$postal_code_arrays = array_filter($arr, function($a){
  if(!isset($a['types'])) return false;

  // Or you can use another condition. i.e: if array only contains postal code
  if(in_array('postal_code', $a['types'])) {  
    return true;
  }
  
  return false;
});

这将 return 只包含数组中最后一个的数组：

[
    [
        "long_name" => "GL50 1LR",
        "short_name" => "GL50 1LR",
        "types" => [
            "postal_code"
        ]
    ]
]

Answer 3

尝试array_filter

$postCode = array_filter($arr["address_components"], function($v) {
    return in_array("postal_code", $v["types"]);
})[0]['long_name'];

获得满足条件的更深层元素

get a deeper element which satisfies the condition

php

laravel

laravel-5.8