PowerMock 间谍调用原始方法但 returns 模拟值

Question

我有以下方法，我模拟了私有方法 foo。

public class Foo { 
    public int x;

    public void init() {
        x = foo();
    }

    private int foo() {
        System.out.println("shouldn't print this");
        return 11;
    }
}

当我模拟如下方法时：

@RunWith(PowerMockRunner.class)
@PrepareForTest({Main.class, Foo.class})
public class MainTest {

@Test
public void foo() throws Exception {
    Foo f = PowerMockito.spy(new Foo());
    PowerMockito.whenNew(Foo.class).withAnyArguments().thenReturn(f);
    PowerMockito.when(f, "foo").thenReturn(42);

    Main m = new Main();
    m.f.init();
    System.out.println(m.f.x);
}

}

它打印 42 而不是 11，这是正确的，但它也打印 shouldn't print this.

是否可以在不调用该方法的情况下模拟私有方法？

Answer 1

shouldn' print this 由于以下行而被打印出来。

PowerMockito.when(f, "foo").thenReturn(42);

相反，将行更改为

PowerMockito.doReturn(42).when(f,"foo");

PowerMock 间谍调用原始方法但 returns 模拟值

PowerMock spy calls original method but returns mocked value

java

mockito

powermockito