在图形上执行 DFS 时出现 stackoverflow 错误
Getting stackoverflow error while doing DFS on a graph
我正在对图实施深度优先搜索,以找到所有连通分量的最小总和。但是我收到堆栈溢出错误。我尝试调试它,但失败了。
有人可以帮忙吗?
代码如下:
#include <bits/stdc++.h>
using namespace std;
void DFS(int x, vector<vector<int>> graph, vector<int> cost, vector<bool> visited, int &c)
{
c = min(c, cost[x]);
visited[x] = true;
for (int n = 0; n < (int)graph[x].size(); n++)
{
if (!visited[graph[x][n]])
DFS(x, graph, cost, visited, c);
}
}
void solve()
{
int nodes, edges;
cin >> nodes >> edges;
vector<int> cost(nodes);
vector<bool> visited(nodes);
vector<vector<int>> graph(nodes);
for (int i = 0; i < nodes; i++)
cin >> cost[i];
for (int i = 0; i < edges; i++)
{
int a, b;
cin >> a >> b;
graph[a - 1].push_back(b - 1);
graph[b - 1].push_back(a - 1);
}
int ans = 0;
for (int i = 0; i < nodes; i++)
{
if (!visited[i])
{
int c = cost[i];
DFS(i, graph, cost,visited, c);
ans += c;
}
}
cout << ans << "\n";
}
int main()
{
ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0);
solve();
}
当然
DFS(x, graph, cost, visited, c);
应该是
DFS(graph[x][n], graph, cost, visited, c);
你真的应该在调试器中注意到这一点。
我正在对图实施深度优先搜索,以找到所有连通分量的最小总和。但是我收到堆栈溢出错误。我尝试调试它,但失败了。
有人可以帮忙吗?
代码如下:
#include <bits/stdc++.h>
using namespace std;
void DFS(int x, vector<vector<int>> graph, vector<int> cost, vector<bool> visited, int &c)
{
c = min(c, cost[x]);
visited[x] = true;
for (int n = 0; n < (int)graph[x].size(); n++)
{
if (!visited[graph[x][n]])
DFS(x, graph, cost, visited, c);
}
}
void solve()
{
int nodes, edges;
cin >> nodes >> edges;
vector<int> cost(nodes);
vector<bool> visited(nodes);
vector<vector<int>> graph(nodes);
for (int i = 0; i < nodes; i++)
cin >> cost[i];
for (int i = 0; i < edges; i++)
{
int a, b;
cin >> a >> b;
graph[a - 1].push_back(b - 1);
graph[b - 1].push_back(a - 1);
}
int ans = 0;
for (int i = 0; i < nodes; i++)
{
if (!visited[i])
{
int c = cost[i];
DFS(i, graph, cost,visited, c);
ans += c;
}
}
cout << ans << "\n";
}
int main()
{
ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0);
solve();
}
当然
DFS(x, graph, cost, visited, c);
应该是
DFS(graph[x][n], graph, cost, visited, c);
你真的应该在调试器中注意到这一点。