MediaPlayer 问题：同时播放所有歌曲

Question

所以我正在尝试播放用户选择的特定歌曲组合。我正在制作一个字符串数组，这些字符串是应该在 MediaPlayer 中播放的文件名。问题是所有歌曲同时播放。我已经尝试了所有方法，但仍然不知道如何确保播放器在开始下一首歌曲之前等待一首歌曲结束。

这是我尝试过的方法：

public void play(View v){

        if(player==null)
        {
            while(true) {
                if(i==brojac) break; //checking if the arraylist has ended
                if(player.isPlaying()==false) {
                    i++;
                    String s = lista.get(i).toString();
                    player = MediaPlayer.create(this, (this.getResources().getIdentifier(s, "raw", this.getPackageName())));
                    player.setOnCompletionListener(new MediaPlayer.OnCompletionListener() {
                        @Override
                        public void onCompletion(MediaPlayer mediaPlayer) {
                            stopPlayer();
                        }
                    });
                    player.start();
                }
            }
        }

    }

private void stopPlayer()
    {
        if(player!=null)
        {
            player.release();
            player=null;
        }
    }

编辑

有了下面的答案，一切正常，但玩家有明显的差距。我已经用 setNextPlayer() 函数解决了它，但是由于在播放时重新创建播放器，应用程序崩溃了。

void playSong(int currentSong) {
        player = MediaPlayer.create(this, currentSong);
        player1 = MediaPlayer.create(this,this.getResources().getIdentifier(lista.get(i+1).toString(),"raw",getPackageName()));
        player.setNextMediaPlayer(player1);
        player.setOnCompletionListener(new MediaPlayer.OnCompletionListener() {
            @Override
            public void onCompletion(MediaPlayer mp) {
                player.release();
                i++;
                if(i==brojac) return;
                player1.start();
                playSong(MainActivity.this.getResources().getIdentifier(lista.get(i).toString(),"raw",getPackageName()));
            }
        });
        if(i==0) {
            player.start();
        }
    }

Answer 1

我相信你想要这个：

ArrayList<Integer> songs = new ArrayList<>();
    private MediaPlayer mediaPlayer;
    private int currentIndex = 0;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Field[] fields = R.raw.class.getFields();
        for (Field field : fields)
            songs.add(getResources().getIdentifier(field.getName(), "raw", getPackageName()));
        playSong(songs.get(currentIndex));

    }


    void playSong(int currentSong) {
        mediaPlayer = MediaPlayer.create(this, currentSong);
        mediaPlayer.setOnCompletionListener(completeListener);
        mediaPlayer.start();
    }

    MediaPlayer.OnCompletionListener completeListener = mp -> {
        mp.release();
        currentIndex++;
        playSong(songs.get(currentIndex));
    };

解释：

下面的代码将从 raw 文件夹中获取所有音频文件并将它们存储在 ArrayList 名为 songs :

 Field[] fields = R.raw.class.getFields();
 for (Field field : fields)
            songs.add(getResources().getIdentifier(field.getName(), "raw", getPackageName()));

要播放歌曲：

void playSong(int currentSong) {
        mediaPlayer = MediaPlayer.create(this, currentSong);
        mediaPlayer.setOnCompletionListener(completeListener);
        mediaPlayer.start();
    }

OnCompletionListener 听众，当歌曲结束时，您需要增加 currentIndex 这样 songs.get(currentIndex) 就会给您下一首歌曲

MediaPlayer.OnCompletionListener completeListener = mp -> {
        mp.release();
        currentIndex++;
        playSong(songs.get(currentIndex));
    };

MediaPlayer 问题：同时播放所有歌曲

MediaPlayer problem: all songs playing at the same time

java

android

windows-media-player

android-mediaplayer