使用 Redis 从存储的集合中获取所有唯一分数？

Question

要添加地理数据，请使用以下代码

jedis.geoadd("storegeodata", 51.5074, 0.1278, "London");
//while member string is mostly json 
jedis.geoadd("storegeodata", 51.5074, 0.1278, "{place: London}");
jedis.geoadd("storegeodata", 51.5074, 0.1278, "{place: London, lat: 51.5074, lon: 0.1278}");

虽然 geohash 因成员字符串不同而重复，如何检索唯一的基于 geohash 的值避免冗余

public Map<String, Object> checkRedisGeo(double lat, double lon, Jedis j) {
    Map<String, Object> result = new HashMap<>();
    try
    {
        GeoRadiusParam param = GeoRadiusParam.geoRadiusParam();
        param.sortAscending();
        param.withDist();
        param.count(1);
        System.out.println("lat :"+lat+" , lon :"+lon);
        List<GeoRadiusResponse> response =  j.georadius("commander",
                lon,lat, 150, GeoUnit.M, param);    
        //System.out.println(response.size()+" size");
      if(response.size() > 0)
      {
          for (GeoRadiusResponse geoRadiusResponse : response) {
                System.out.println("lat :"+lat+" , lon :"+lon+",  stringmember :"+geoRadiusResponse.getMemberByString());
                //System.out.println(geoRadiusResponse.getDistance());
                Object[] data= {geoRadiusResponse.getMemberByString()};
                System.out.println(data);
                result.put("result", data);
        
               }
      }else {
         // sendEvents(streamEvent, null, streamEventChunk);
          System.out.println("E");
      }
      
    } catch (Exception e) {
        LOGGER.error("checkRedisGeo err : "+e);
    }
      
  return result;
    
}

哪个检索结果但是如何根据geohash/分值过滤掉，如何得到所有不同的分数？

以下是样本冗余数据

Answer 1

能够通过比较分数获得重复和独特的分数，因为分数是唯一的并且多个成员存储相同的分数以下是相同的代码

    Double previous_score = 0.0;
    int DuplincatesCount = 0;
    int UniqueCount = 0;
    Set<String> values = jedis.zrange("rediskey", 0, -1);// get all the members
    for (String member : values) {
        Double current_score = jedis.zscore("rediskey", member);//each member looped
        if (Double.compare(current_score, previous_score) == 0) { //comparing current score with previous
                                                                    // score
            DuplincatesCount++;
        } else {
            UniqueCount++;
        }
        previous_score = current_score;// score mapping
    }
    System.out.println("Duplincates entry " + DuplincatesCount);
    System.out.println("Unique entry " + UniqueCount);

使用 Redis 从存储的集合中获取所有唯一分数？

Fetch all unique scores from a stored set with Redis?

java

gis

redis

jedis