Lua:在两个特定列上迭代 table(使用字母数字值)

Lua: iterate table (with alphanumeric values) on two specific columns

我有这段代码迭代 Lua table“childrenTable”来检索它的值,但我希望它们按列 排序 "symbolicname" 然后,按列 "name"


    local JSON = require 'dkjson'

    local childrenTable = {}
    
    childrenTable[1] = {symbolicname = "02 CONNECTOR", path = "system/core/b connector", name = "b connector"}
    childrenTable[2] = {symbolicname = "02 CONNECTOR", path = "system/core/a connector", name = "a connector"}
    childrenTable[3] = {symbolicname = "01 CORE", path = "/system/core/b", name = "b"}

    childrenTable[4] = {symbolicname = "01 CORE", path = "/system/core/a", name = "a"}    
        
    for index,value in ipairs(childrenTable) do print(JSON.encode(value)) end

这是 return 的结果:

{"name":"b connector","symbolicname":"02
CONNECTOR","path":"system/core/b connector"}

{"name":"a connector","symbolicname":"02
CONNECTOR","path":"system/core/a connector"}

{"name":"b","symbolicname":"01 CORE","path":"/system/core/b"}

{"name":"a","symbolicname":"01 CORE","path":"/system/core/a"}

但我希望它按顺序 return 列表:

{"name":"a","symbolicname":"01 CORE","path":"/system/core/a"}

{"name":"b","symbolicname":"01 CORE","path":"/system/core/b"}

{"name":"a connector","symbolicname":"02
CONNECTOR","path":"system/core/a connector"}

{"name":"b connector","symbolicname":"02
CONNECTOR","path":"system/core/b connector"}

提前致谢,

罗杰

使用table.sort函数,它会遍历table并在当前索引的左右翼传递给你一个项目。 (table.sort基于快速排序算法)

这对你有用:

local childrenTable = {}
childrenTable[1] = {symbolicname = "02 CONNECTOR", path = "system/core/b connector", name = "b connector"}
childrenTable[2] = {symbolicname = "02 CONNECTOR", path = "system/core/a connector", name = "a connector"}
childrenTable[3] = {symbolicname = "01 CORE", path = "/system/core/b", name = "b"}
childrenTable[4] = {symbolicname = "01 CORE", path = "/system/core/a", name = "a"} 

table.sort(childrenTable, function(a, b)
    if a.symbolicname < b.symbolicname then
        return true
    else
        if a.name < b.name then
            return true
        else return false end
    end
    return false
end)

for k,v in pairs(childrenTable) do print(k, v.name, v.symbolicname) end

此外,对于大量数据,请考虑使用数据框。