如何检查：数组是否正确包含特定文本？

Question

我正在努力进行数组搜索，其中包含一段必须包含反斜杠的文本。我已经尝试 includes(''); 否定 includes(''); 并尝试使用 indexOf('').

进行类似的尝试

我有一个简单的数组，最多有四个值；通常它有两个，这是它通常的样子：

{tks: Array(2)}
tks: Array(2)
0: "https://mycoolwebsite.net/arcgis/rest/services"
1: "https://mycoolwebsite.com/arcgis/rest/services"
length: 2
__proto__: Array(0)
__proto__: Object

以下是我尝试执行的简单检查：我对 *includes* 'wdt' 文本的第二次检查似乎有效，所以 我认为它是带有反斜杠的东西。无论如何我可以处理这个？ 我很困惑为什么我的 if 和 else 都在下面使用反斜杠的第一次检查中被击中......我添加了否定 else 仔细检查.. 在 else 中有和没有它，else 总是被击中。

    // right before doing the search I am building the array, just to add more context

    for (let i = 0; i < coolObj.length; i++) {
      if (coolObj[i].url){
          tr = coolObj[i].url;
          tks.push(tr);

          console.log({tks});     
       }
     }

    console.log({tks}); // consoles as I have included above ^

    if (tks.includes('/arcgis/rest/services')) {
            
      console.log({tks});     

    } else if (!tks.includes('/arcgis/rest/services')) { 

      console.log({tks});

      console.log('does not include correct url');
      aT = '/arcgis/rest/services';
      lP = false;
      filterAt(aT);
    }
    if (tks.includes('wdt')) {
      console.log({tks});

    }else {
      console.log({tks});
      wT = 'wdt';
      filterWt(wT);
    }

Answer 1

来自MDN docs：includes() 方法确定数组的条目中是否包含某个值，并根据需要返回 true 或 false。

您必须在数组元素中使用 String.prototype.includes 测试字符串，因此：

const arr = ["https://mycoolwebsite.net/arcgis/rest/services", "https://mycoolwebsite.com/arcgis/rest/services"];

arr.forEach(el => {
  if (el.includes('/arcgis/rest/services')) {
    console.log(el, ': includes url');
  }
  else {
    console.log('does not include correct url');
  }
  if (el.includes('wdt')) {
    console.log(el, ': includes wdt');
  } else {
    console.log('does not include correct wdt');

  }

});

如何检查：数组是否正确包含特定文本？

how to check: if array includes specific text properly?

javascript

arrays

string

indexof