在 Powershell 中用不同的值查找并替换 JSON 中某个值的所有实例

Find and Replace all instances of a value in JSON with different value in Powershell

我有一个大 JSON 值需要用其他值替换。基本上我正在尝试在 powershell 中查找和替换所有内容。我想删除我们看到 Rock to Rocky 的地方

JSON

{
  "Customer": [
    {
      "id": "123"
    }
  ],
  "Nationality": [
    {
      "name": "US",
      "id": "456"
    }
  ],
  "address": [
    {
      "$type": "Home",
      "name": "Houston",
      "streets": [
        {
          "name": "Union",
          "postalCode": "10",
        }
      ]
    },
    {
      "$type": "Office",
      "name": "Hawai",
      "streets": [
        {
          "name": "Rock",
          "postalCode": "11",
        }
      ]
    },
    {
      "$type": "Office1",
      "name": "Hawaii",
      "streets": [
        {
          "name": "Rock 678",
          "postalCode": "11",
        }
      ]
    },
    {
      "$type": "Office2",
      "name": "Hawai2",
      "streets": [
        {
          "name": "Rock",
          "postalCode": "11",
        }
      ]
    }
    
  ]
}

我正在将 JSON 更改为对象,但不确定如何找到并替换所有内容。我想删除我们看到 Rock to Rocky 的地方

代码

$FileContent = Get-Content -Path "Test.json" -Raw | ConvertFrom-Json
$FileContent.address.streets.name = 'Rocky' // I want to do for all the instances.

$FileContent | ConvertTo-Json -Depth 100 | Out-File "Test.json" -Force

如何使用 Powershell 替换文件中的字符串值?

  • 用'Rocky'替换'Rock';

  • Set-Content 在文件中。

    (Get-Content -path C:\Users\Username\Folder\File.json -Raw) -replace 'Rock' , 'Rocky' | Set-Content -path C:\Users\Username\Folder\File.json;