如何计算从现在起加上n天的总秒数

Question

我想在每周二 12:00pm

发送通知

我想在周二 12:00pm

之前获得未来的准确时间（以秒为单位）

import datetime
from datetime import date , timedelta

today = datetime.date.today()
Tuesday = datetime.timedelta( (1-today.weekday()) % 7 ) + timedelta(hours=12)
seconds_to_call = Tuesday.total_seconds() 

print(seconds_to_call)

# Gives exactly 5 days in seconds 432,000 + timedelta(hours=12) 43200

# 以秒为单位给出 5 天 432,000 + timedelta(hours=12) 43200

如何获得星期二 00:00 加上 12 小时的时间增量（小时=12）43200

那么我会在星期二中午 12 点

谢谢

Answer 1

第一题

I want to get an exact time in the future in seconds until Tuesday at 12:00pm

我想你想要从今天

到星期二12:00的确切时间（以秒为单位）

import datetime

def relative_date(reference, weekday, timevalue):
    hour, minute = divmod(timevalue, 1)
    minute *= 60
    days = reference.weekday()+(reference.weekday() - weekday)
    return (reference + datetime.timedelta(days=days)).replace(hour=int(hour), minute=int(minute), second=0, microsecond=0)

today = datetime.datetime.now()
Tuesday = relative_date(today, 1, 12)

seconds_to_call = (Tuesday - today).total_seconds()

print(seconds_to_call)

# OUTPUT: 405778.097769

你必须计算今天和下周二这两个日期之间的差异。函数 relative_date 计算下周二的确切日期并将小时设置为 12:00:00.000.

第二个问题

I want to run the program get the number of seconds until 00:00 then had the number of seconds until 12 (43,200)

你可以这样做：

import datetime

def relative_date(reference, weekday, timevalue):
    hour, minute = divmod(timevalue, 1)
    minute *= 60
    days = reference.weekday()+(reference.weekday() - weekday)
    return (reference + datetime.timedelta(days=days)).replace(hour=int(hour), minute=int(minute), second=0, microsecond=0)

today = datetime.datetime.now()
Tuesday_midnight = relative_date(today, 1, 0)

seconds_to_call = ((Tuesday_midnight - today) + datetime.timedelta(hours=12)).total_seconds()

print(seconds_to_call)

# OUTPUT: 405778.097769

在这种情况下计算到午夜的时间是没有用的，你可以得到total_seconds，如第一题的代码，直接从中午开始。

Answer 2

from datetime import datetime, timedelta

# get the date and time for now
now = datetime.now()

# get the current day at midnight
today = now.replace(hour=0, minute=0, second=0, microsecond=0)

# get Tuesday at midnight
tues = today + timedelta( (1-today.weekday()) % 7 )

# get the seconds from now until Tuesday at midnight
seconds_to_tues_midnight = (tues - now).total_seconds()

# get the seconds from now until Tuesday at noon
seconds_to_tues_noon = seconds_to_tues_midnight + timedelta(hours=12)/timedelta(seconds=1)

作为函数

from typing import Tuple

def time_to_tuesday(now: datetime) -> Tuple[float, float]:
    today = now.replace(hour=0, minute=0, second=0, microsecond=0)
    tues = today + timedelta( (1-today.weekday()) % 7 )
    midnight = (tues - now).total_seconds()
    noon = midnight + timedelta(hours=12)/timedelta(seconds=1)
    
    return midnight, noon


time_to_tuesday(datetime.now())

如何计算从现在起加上n天的总秒数

How to calculate the total seconds from now plus n days

python

datetime

timedelta

第一题

第二个问题

作为函数