想要将多次出现的 # 替换为 //

Question

transform_comments 函数将 Python 脚本中的注释转换为 C 编译器可用的注释。这意味着查找以散列标记 (#) 开头的文本并将其替换为双斜杠 (//)，这是 C 单行注释指示器。出于本练习的目的，我们将忽略 Python 命令中嵌入哈希标记的可能性，并假设它仅用于表示注释。我们还想将重复的散列标记 (##)、(###) 等视为单个评论指示符，仅替换为 (//) 而不是 (#//) 或 (//#)。填写替换方法的参数即可完成此功能

这是我的尝试：

import re

def transform_comments(line_of_code):
  result = re.sub(r'###',r'//', line_of_code)
  return result

print(transform_comments("### Start of program")) 
# Should be "// Start of program"
print(transform_comments("  number = 0   ## Initialize the variable")) 
# Should be "  number = 0   // Initialize the variable"
print(transform_comments("  number += 1   # Increment the variable")) 
# Should be "  number += 1   // Increment the variable"
print(transform_comments("  return(number)")) 
# Should be "  return(number)"

Answer 1

使用 * 正则表达式运算符

def transform_comments(line_of_code):
  result = re.sub(r'##*',r'//', line_of_code)
  return result

来自 re 库文档

* Causes the resulting RE to match 0 or more repetitions of the preceding RE, as many repetitions as are possible. ab* will match a, ab, or a followed by any number of bs.

Answer 2

import re
def transform_comments(line_of_code):
    result = re.sub(r"#{1,}",r"//", line_of_code)
    return result

Answer 3

import re
def transform_comments(line_of_code):
  result = re.sub(r'(#*#) ',r'// ',line_of_code)
  return result

Answer 4

我们可以使用 + 来表示一次或多次出现 #

result = re.sub(r"#+",r"//",line_of_code)

Answer 5

以下代码有效：

result = re.sub(r"[#]+","//",line_of_code)

想要将多次出现的 # 替换为 //

Want to replace multiple occurances of # to //

python

regex

python-re