对于以下情况，如何在 oracle sql 中执行类似 unpivot 的操作？

Question

这是 table 语句，我想将数据转换成一些不可逆的东西，比如只使用 sql。

create table galy(
pro_Date date,
profit number
);
insert into galy values(sysdate-1,30);
insert into galy values(sysdate,20);
insert into galy values(sysdate+1,40);
insert into galy values(sysdate+2,50);
insert into galy values(sysdate+3,70);
commit;

单个查询中需要输出（不应考虑周六和周日的日期）

      Date                  d-1                    d                d+1
    01-02-2018(sysdate)      30                    20                40
     ....
     ....

Answer 1

不需要 pivot/unpivot 就可以让数据以您想要的格式显示。只要每天只有1个PRO_DATE，就可以使用LEAD和LAG解析函数

查询

SELECT pro_date,
       LAG (profit) OVER (ORDER BY pro_date)     AS prior_day_profit,
       profit                                    AS current_day_profit,
       LEAD (profit) OVER (ORDER BY pro_date)     AS next_day_profit
  FROM galy;

结果

    PRO_DATE    PRIOR_DAY_PROFIT    CURRENT_DAY_PROFIT    NEXT_DAY_PROFIT
____________ ___________________ _____________________ __________________
04-OCT-20                                           30                 20
05-OCT-20                     30                    20                 40
06-OCT-20                     20                    40                 50
07-OCT-20                     40                    50                 70
08-OCT-20                     50                    70

更新

要排除周末，您只需在查询中添加一个 where 子句

SELECT pro_date,
       LAG (profit) OVER (ORDER BY pro_date)      AS prior_day_profit,
       profit                                     AS current_day_profit,
       LEAD (profit) OVER (ORDER BY pro_date)     AS next_day_profit
  FROM galy
 WHERE TO_CHAR (pro_date, 'DY') NOT IN ('SAT', 'SUN');

对于以下情况，如何在 oracle sql 中执行类似 unpivot 的操作？

How to do something like unpivot like in oracle sql for the following scenario?

sql

oracle

unpivot

查询

结果

更新