如何在 POSIX 共享内存中使用结构?
How to use struct in POSIX shared memory?
我希望我的 POSIX 共享内存段符合特定结构。我认为这段代码以结构的形式创建了共享内存段。
(File creating the shared memory segment)
typedef struct {
int cnt;
char buf[segsize];
} shmseg_t;
int shm_fd = shm_open(shm_name, O_CREAT | O_RDWR, 0666);
ftruncate(shm_fd, sizeof(shmseg_t);
void* addr = mmap(NULL, sizeof(shmseg_t), PROT_READ | PROT_WRITE, MAP_SHARED, shm_fd, 0);
如何将文件中的数据写入共享内存中结构的不同字段?
(File writing to the shared memory segment)
int shm_fd = shm_open(shm_name, O_WRONLY, 0);
ftruncate(shm_fd, segsize);
void* addr = mmap(NULL, segsize, PROT_WRITE, MAP_SHARED, shm_fd, 0);
// How do I get shmp, which should be a shmseg_t struct?
shmp->cnt = read(fd, shmp->buf, segsize);
以及如何取出写入共享内存中结构的数据?
(File reading from the shared memory segment)
int shm_fd = shm_open(shm_name, O_RDONLY, 0);
ftruncate(shm_fd, segsize);
void* addr = mmap(NULL, segsize, PROT_READ, MAP_SHARED, shm_fd, 0);
// How to get out shmp->cnt and shmp->buf?
不清楚您是要共享整个结构还是只共享 buf
。
选项 1: 使 buf
成为一个指针,并分享它指向的内容。
typedef struct {
int cnt;
char *buf;
} shmseg_t;
ftruncate(shm_fd, segsize);
void* addr = mmap(NULL, segsize,
PROT_READ | PROT_WRITE, MAP_SHARED, shm_fd, 0);
assert(addr != MAP_FAILED);
shm_seg_t shmp = {
.cnt = ???, // Whatever value of cnt you want.
.buf = addr,
};
选项 2:共享整个结构。
typedef struct {
int cnt;
char buf[segsize];
} shmseg_t;
ftruncate(shm_fd, sizeof(shmseg_t));
void* addr = mmap(NULL, sizeof(shmseg_t),
PROT_READ | PROT_WRITE, MAP_SHARED, shm_fd, 0);
assert(addr != MAP_FAILED);
shm_seg_t *shmp = addr;
这样分享的话,读和写其实没什么区别(但是需要用到内存屏障或者同步)
我希望我的 POSIX 共享内存段符合特定结构。我认为这段代码以结构的形式创建了共享内存段。
(File creating the shared memory segment)
typedef struct {
int cnt;
char buf[segsize];
} shmseg_t;
int shm_fd = shm_open(shm_name, O_CREAT | O_RDWR, 0666);
ftruncate(shm_fd, sizeof(shmseg_t);
void* addr = mmap(NULL, sizeof(shmseg_t), PROT_READ | PROT_WRITE, MAP_SHARED, shm_fd, 0);
如何将文件中的数据写入共享内存中结构的不同字段?
(File writing to the shared memory segment)
int shm_fd = shm_open(shm_name, O_WRONLY, 0);
ftruncate(shm_fd, segsize);
void* addr = mmap(NULL, segsize, PROT_WRITE, MAP_SHARED, shm_fd, 0);
// How do I get shmp, which should be a shmseg_t struct?
shmp->cnt = read(fd, shmp->buf, segsize);
以及如何取出写入共享内存中结构的数据?
(File reading from the shared memory segment)
int shm_fd = shm_open(shm_name, O_RDONLY, 0);
ftruncate(shm_fd, segsize);
void* addr = mmap(NULL, segsize, PROT_READ, MAP_SHARED, shm_fd, 0);
// How to get out shmp->cnt and shmp->buf?
不清楚您是要共享整个结构还是只共享 buf
。
选项 1: 使 buf
成为一个指针,并分享它指向的内容。
typedef struct {
int cnt;
char *buf;
} shmseg_t;
ftruncate(shm_fd, segsize);
void* addr = mmap(NULL, segsize,
PROT_READ | PROT_WRITE, MAP_SHARED, shm_fd, 0);
assert(addr != MAP_FAILED);
shm_seg_t shmp = {
.cnt = ???, // Whatever value of cnt you want.
.buf = addr,
};
选项 2:共享整个结构。
typedef struct {
int cnt;
char buf[segsize];
} shmseg_t;
ftruncate(shm_fd, sizeof(shmseg_t));
void* addr = mmap(NULL, sizeof(shmseg_t),
PROT_READ | PROT_WRITE, MAP_SHARED, shm_fd, 0);
assert(addr != MAP_FAILED);
shm_seg_t *shmp = addr;
这样分享的话,读和写其实没什么区别(但是需要用到内存屏障或者同步)