如何在 C++ 中打印多个输入和输出?
How do I print multiple inputs and outputs in C++?
我正在尝试解决竞争性编程书籍中的一个问题,其中输出仅在输入最后一个输入后出现。我似乎已经理解了逻辑,但我仍然对如何做 input/output 部分感到困惑。
代码如下:
#include <bits/stdc++.h>
int main()
{
std::ios_base::sync_with_stdio(false);
std::cin.tie(NULL);
std::vector<int>soundex;
std::string word;
for(int i = 0; i < word.length(); i++)
{
if (word[i] == 'B'|| word[i] == 'F' || word[i] == 'P' || word[i] == 'V')
{
soundex.push_back(1);
}
if (word[i] == 'C' || word[i] == 'G' || word[i] == 'J' || word[i] == 'K' || word[i] == 'Q' || word[i] == 'S' || word[i] == 'X' || word[i] == 'Z')
{
soundex.push_back(2);
}
if (word[i] == 'D' || word[i] == 'T')
{
soundex.push_back(3);
}
if (word[i] == 'L')
{
soundex.push_back(4);
}
if (word[i] == 'M' || word[i] == 'N')
{
soundex.push_back(5);
}
if (word[i] == 'R')
{
soundex.push_back(6);
}
}
for (int j = 0; j < soundex.size(); j++)
{
if (soundex[j] == soundex[j+1])
{
soundex.erase(soundex.begin() + 1);
}
std::cout << soundex[j];
}
std::cout << "\n";
return 0;
}
它的行为是这样的:
输入:
KHAWN
输出:
25
输入:
PFISTER
输出:
1236
输入:
BOBBY
输出:
11
但根据问题的说明,我需要它表现得像这样:
输入:
KHAWN
PFISTER
BOBBY
输出:
25
1236
11
使用 while(cin >> word){ ... your code ... }
读取直到 EOF(文件结尾),以防每行只包含一个单词(不允许有空格)。您可以保持输出不变。
我正在尝试解决竞争性编程书籍中的一个问题,其中输出仅在输入最后一个输入后出现。我似乎已经理解了逻辑,但我仍然对如何做 input/output 部分感到困惑。
代码如下:
#include <bits/stdc++.h>
int main()
{
std::ios_base::sync_with_stdio(false);
std::cin.tie(NULL);
std::vector<int>soundex;
std::string word;
for(int i = 0; i < word.length(); i++)
{
if (word[i] == 'B'|| word[i] == 'F' || word[i] == 'P' || word[i] == 'V')
{
soundex.push_back(1);
}
if (word[i] == 'C' || word[i] == 'G' || word[i] == 'J' || word[i] == 'K' || word[i] == 'Q' || word[i] == 'S' || word[i] == 'X' || word[i] == 'Z')
{
soundex.push_back(2);
}
if (word[i] == 'D' || word[i] == 'T')
{
soundex.push_back(3);
}
if (word[i] == 'L')
{
soundex.push_back(4);
}
if (word[i] == 'M' || word[i] == 'N')
{
soundex.push_back(5);
}
if (word[i] == 'R')
{
soundex.push_back(6);
}
}
for (int j = 0; j < soundex.size(); j++)
{
if (soundex[j] == soundex[j+1])
{
soundex.erase(soundex.begin() + 1);
}
std::cout << soundex[j];
}
std::cout << "\n";
return 0;
}
它的行为是这样的:
输入:
KHAWN
输出:
25
输入:
PFISTER
输出:
1236
输入:
BOBBY
输出:
11
但根据问题的说明,我需要它表现得像这样:
输入:
KHAWN
PFISTER
BOBBY
输出:
25
1236
11
使用 while(cin >> word){ ... your code ... }
读取直到 EOF(文件结尾),以防每行只包含一个单词(不允许有空格)。您可以保持输出不变。