YamlDotNet

Question

我有一个 .NET class 代表一个 RPC 方法调用，像这样：

class MethodCall
{
    public string MethodName { get; set; }
    public Collection<object> Arguments { get; set; }
}

我想将 Collection<MethodCall> 序列化为 YAML。我正在使用 YamlDotNet 来实现这一点。

默认情况下，YamlDotNet 将像这样序列化这些对象：

methodName: someName
arguments:
- arg1
- arg2
- ...

我想将生成的 YAML 简化为：

someName:
- arg1
- arg2

有什么简单的方法可以做到这一点吗？请注意，参数可以是复杂的对象（即不是简单的标量）。

Answer 1

您可以通过注册执行所需转换的 IYamlTypeConverter 实现来实现此目的。

这是一个可能的实现：

public sealed class MethodCallConverter : IYamlTypeConverter
{
    // Unfortunately the API does not provide those in the ReadYaml and WriteYaml
    // methods, so we are forced to set them after creation.
    public IValueSerializer ValueSerializer { get; set; }
    public IValueDeserializer ValueDeserializer { get; set; }
    
    public bool Accepts(Type type) => type == typeof(MethodCall);

    public object ReadYaml(IParser parser, Type type)
    {
        parser.Consume<MappingStart>();

        var call = new MethodCall
        {
            MethodName = (string)ValueDeserializer.DeserializeValue(parser, typeof(string), new SerializerState(), ValueDeserializer),
            Arguments = (Collection<object>)ValueDeserializer.DeserializeValue(parser, typeof(Collection<object>), new SerializerState(), ValueDeserializer),
        };

        parser.Consume<MappingEnd>();
        
        return call;
    }
    
    public void WriteYaml(IEmitter emitter, object value, Type type)
    {
        emitter.Emit(new MappingStart());

        var call = (MethodCall)value;
        ValueSerializer.SerializeValue(emitter, call.MethodName, typeof(string));
        ValueSerializer.SerializeValue(emitter, call.Arguments, typeof(Collection<object>));

        emitter.Emit(new MappingEnd());
    }
}

转换器需要通过WithTypeConverter方法注册到SerializerBuilder和DeserializerBuilder中。请注意，YamlDotNet 没有为我们提供递归调用（反）序列化器的方法，因此我们必须设置一些 public 属性作为解决方法。这并不像它应该的那样干净，但仍然有效：

string SerializeMethodCall(MethodCall call)
{
    var methodCallConverter = new MethodCallConverter();
    var serializerBuilder = new SerializerBuilder()
        .WithNamingConvention(CamelCaseNamingConvention.Instance)
        .WithTypeConverter(methodCallConverter);

    methodCallConverter.ValueSerializer = serializerBuilder.BuildValueSerializer();

    var serializer = serializerBuilder.Build();

    var yaml = serializer.Serialize(call);
    return yaml;
}

MethodCall DeserializeMethodCall(string yaml)
{
    var methodCallConverter = new MethodCallConverter();
    var deserializerBuilder = new DeserializerBuilder()
        .WithNamingConvention(CamelCaseNamingConvention.Instance)
        .WithTypeConverter(methodCallConverter);

    methodCallConverter.ValueDeserializer = deserializerBuilder.BuildValueDeserializer();

    var deserializer = deserializerBuilder.Build();
    var call = deserializer.Deserialize<MethodCall>(yaml);
    return call;
}

YamlDotNet - 自定义序列化

YamlDotNet - Custom Serialization

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