有没有更古怪的方法来生成这个虚拟数据?

Is there a less oddball way to generate this dummy data?

输入:word_types的列表,例如[“动词”、“形容词”、“名称”、“名词”

期望的输出:每个 letter-word_type 组合的三个单词的字典 word_type。

{“verbs”:[“Averb1”,“Averb2”,“Averb3”],[Bverb1,...],...,“形容词”:[“Aadjective1”,“Aadjectives2”,“ AAdjectives3"] ...等

这是我用来生成数据的。

import string
A_to_Z = list(string.ascii_uppercase)  #  list of letters a-z
lettered_word_types = ["verb", "adjective", "name", "noun"]

class Lexicon:
    def __init__(self, testing = True):
        if testing == True:
            for TYPE in lettered_word_types:
                setattr(self, TYPE + "s", [letter + TYPE for letter in A_to_Z])
        self.__dict__ = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in self.__dict__.items()}


data = Lexicon().__dict__

class 没有任何作用,它只会混淆您的操作。要直接音译您的代码以使用 dict,您只需要:

result = {}
for TYPE in lettered_word_types:
    result[TYPE + 's'] = [letter + TYPE for letter in A_to_Z]
result = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in result.items()}

所以,只是为了证明这确实是等价的:

In [1]: import string
    ...: A_to_Z = list(string.ascii_uppercase)  #  list of letters a-z
    ...: lettered_word_types = ["verb", "adjective", "name", "noun"]
    ...:
    ...: class Lexicon:
    ...:     def __init__(self, testing = True):
    ...:         if testing == True:
    ...:             for TYPE in lettered_word_types:
    ...:                 setattr(self, TYPE + "s", [letter + TYPE for letter in A_to_Z])
    ...:         self.__dict__ = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in self.__dict__.items()}
    ...:
    ...:
    ...: data = Lexicon().__dict__

In [2]: result = {}

In [3]: for TYPE in lettered_word_types:
    ...:     result[TYPE + 's'] = [letter + TYPE for letter in A_to_Z]
    ...:

In [4]: result = {key: [[element + "1", element + "2", element + "3"] for element in value] for key, value in result.items()}

In [5]: result == data
Out[5]: True