有人能找到错误 "a value of type "void" cannot be assigned to an entity of type "int" " in VScode 的原因吗？

Question

代码如下：

ssize_t readline(int fd, void *buf, size_t maxlen)
{
    char c;
    char * bufp=buf;
    int n;
    
    for(n = 0; n < maxlen - 1; n++)
    {
        int kk;
        if((kk = read_or_die(fd, &c, 1)) == 1) // **Intellisense throws error here**
        {
            *bufp++ = c; 
            if(c == '\n')
            break;               
        }

        else if (kk == 0)
        {
            if(n == 0) 
                return 0;

            else
                break;  
        }

        else
            return -1;

    }
    bufp = '[=13=]';
    return n;


}

函数的定义read_or_die定义如下：

#define read_or_die(fd, buf, count) \
    ({ssize_t rc = read(fd, buf, count); assert(rc >= 0); rc: })

从这个link我了解到rc是从read_or_die ()返回的。显然，rc 是 ssize_t 类型而不是 void.

为什么 VScode intellisense 在 if((kk = read_or_die(fd, &c, 1)) == 1) 抛出这个错误？

Answer 1

在宏的末尾添加分号是解决方案。

#define read_or_die(fd, buf, count) \
    ({ssize_t rc = read(fd, buf, count); assert(rc >= 0); rc; })

有人能找到错误 "a value of type "void" cannot be assigned to an entity of type "int" " in VScode 的原因吗？

Can some one please find the reason for the error "a value of type "void" cannot be assigned to an entity of type "int" " in VScode?

c

visual-studio-code

intellisense