GRAPHVIZ：强制节点到页面顶部

Question

我正在使用 graphviz，但是我想强制节点“This on top”到页面顶部，而不是侧面。这是图表：

这是代码：

g= Digraph('trial', filename='trial.gv')
g.attr(compound='true', rankdir="TB" )

with g.subgraph() as s:
  s.attr(rank='max')
  s.node('This on top ')
  s.edge('this right under', "Fabrication")

with g.subgraph(name='cluster0') as c:
    c.node("This")

    c.node("that")
    c.node("and this on the same level")
g.edge("this right under","that", lhead="cluster0" )
g.edge("that","This on top ", ltail="cluster0" )

g

是否有命令确保节点按我希望的 TOP/Bottom 顺序显示？

Answer 1

第一个问题是设置rank='max'强制第一个子图中的所有内容都达到最大等级，即最低等级。您可能打算设置 rank='min' 将子图中的项目置于最高级别，但仍然不会创建您想要的排列。

相反，您可以通过在创建边时设置 style = 'invis' 来使用不可见的边，以强制“这个在上面”出现在“这个在下面”之前。

from graphviz import Digraph

g= Digraph('trial', filename='trial.gv')
g.attr(compound='true', rankdir="TB" )

with g.subgraph() as s:
  # s.attr(rank='min') # you don't need this line
  s.node('This on top ')
  s.edge('This on top ', 'this right under', style='invis') # add this invisible edge
  s.edge('this right under', "Fabrication")

with g.subgraph(name='cluster0') as c:
    c.node("This")

    c.node("that")
    c.node("and this on the same level")
g.edge("this right under", "that", lhead="cluster0" )
g.edge("that", "This on top ", ltail="cluster0", constraint="false" )

g

产生：

GRAPHVIZ：强制节点到页面顶部

GRAPHVIZ: Force node to top of page

python

graphviz

pygraphviz