如何用 python 列表中的 int 替换字符串？

Question

在下面的列表中，我想用 0 替换“Sun”，用 1 替换“Rain”。我该怎么做？

precipitation = ["Sun", "Rain", "Rain", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Rain", "Rain", "Rain", "Rain"]

for i in precipitation:  
  if precipitation[i] == "Sun":
    precipitation[i] = 0
  else:
    precipitation[i] = 1

Answer 1

您可以使用列表推导来做到这一点：

precipitation = [0 if x == 'Sun' else 1 for x in precipitation]

Answer 2

试试这个...

precipitation = ["Sun", "Rain", "Rain", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Rain", "Rain", "Rain", "Rain"]

for i in range(len(precipitation)):  
  if precipitation[i] == "Sun":
    precipitation[i] = 0
  else:
    precipitation[i] = 1
         
print(precipitation)

Answer 3

@Gabip 的答案的详细说明，使用布尔值在数字上表示为 0 和 1 的事实：

[int(x=='Sun') for x in precipitation]

Answer 4

使用 map()

添加到已经存在的答案中

list(map(lambda x: 0 if x=='Sun' else 1,a))

您可以试试这个来避免循环和列表理解

如何用 python 列表中的 int 替换字符串？

How to replace string with an int in list in python?

python

string

integer

list

python-3.x