函数类型的左值是否是可修改的左值？

Question

6.3.2.1 C11 标准中的左值、数组和函数指示符说

A modifiable lvalue is an lvalue that does not have array type, does not have an incomplete type, does not have a const- qualified type, and if it is a structure or union, does not have any member (including, recursively, any member or element of all contained aggregates or unions) with a const- qualified type.

函数类型的左值是否是可修改的左值？

引用没有提到函数类型，但实际上，我认为函数类型的左值不是可修改的左值。 （数组类型的左值和函数类型的左值也有一些相似之处：都被转换为数组和函数的地址。）

谢谢。

Answer 1

Is an lvalue of a function type a modifiable lvalue or not?

该问题用词不当。根据定义，左值仅指定一个对象。在您引用的段落 (p1) 的前面，它指定

An lvalue is an expression (with an object type other than void) that potentially designates an object;

函数不计入对象的定义，因此没有函数类型的左值。

相反，函数类型有一个单独的类别。同样在第 6.3.2.1 节中，第 4 段：

A function designator is an expression that has function type. Except when it is the operand of the sizeof operator, the _Alignof operator, or the unary & operator, a function designator with type ''function returning type'' is converted to an expression that has type ''pointer to function returning type''.

所以这个问题基本上没有实际意义。根据左值指定事物的表达式不必关心函数类型。相反，如果适用，表达式的规范将提及它如何使用“函数指示符”

I think an lvalue of a function type is not a modifiable lvalue

正确，但这又是因为根本不计入左值。