使用 SQL 服务器和 PHP 显示存储过程的结果
Display results from Stored Procedure using SQL Server and PHP
我正在尝试使用 PHP 和 SQL 服务器显示存储过程的输出。存储过程是一个 SELECT
语句。截至目前,我最终处于显示成功消息的 else
条件,但我无法显示查询结果。这是函数:
function account_search_sp($account_number,$occupant_code,$name,$address,$bill_code,$utility_code){
global $db;
sqlsrv_configure("WarningsReturnAsErrors", 0);
$sql = "EXEC sp_cigar_account_search @AcctNo= ?, @OccupantCode= ?, @Name= ?, @Address= ?, @BillCode= ?, @UtilityType= ?";
$procedure_params = array(
array(&$account_number, SQLSRV_PARAM_IN),
array(&$occupant_code, SQLSRV_PARAM_IN),
array(&$name, SQLSRV_PARAM_IN),
array(&$address, SQLSRV_PARAM_IN),
array(&$bill_code, SQLSRV_PARAM_IN),
array(&$utility_code, SQLSRV_PARAM_IN)
);
$stmt = sqlsrv_prepare($db, $sql, $procedure_params);
$result = sqlsrv_execute($stmt);
if( !$result ) {
//Show errors
echo "Die error <br>";
die( print_r( sqlsrv_errors(), true));
}else{
echo "<br><h3>Success</h3><br>";
sqlsrv_next_result($stmt);
}
return $stmt; }
如果我 运行 SSMS 中的存储过程例如使用 200 作为帐号,我会取回数据。
我正在使用 PHP 7.4
感谢任何帮助。如果我需要包含更多信息,请告诉我。
如果我理解正确,您需要使用 sqlsrv_ferch_array()
或 sqlsrv_fetch_object()
:
获取数据
<?
function account_search_sp($account_number, $occupant_code, $name, $address, $bill_code, $utility_code) {
global $db;
sqlsrv_configure("WarningsReturnAsErrors", 0);
$sql = "EXEC sp_cigar_account_search @AcctNo= ?, @OccupantCode= ?, @Name= ?, @Address= ?, @BillCode= ?, @UtilityType= ?";
$procedure_params = array(
array(&$account_number, SQLSRV_PARAM_IN),
array(&$occupant_code, SQLSRV_PARAM_IN),
array(&$name, SQLSRV_PARAM_IN),
array(&$address, SQLSRV_PARAM_IN),
array(&$bill_code, SQLSRV_PARAM_IN),
array(&$utility_code, SQLSRV_PARAM_IN)
);
$stmt = sqlsrv_prepare($db, $sql, $procedure_params);
if ($stmt === false) {
echo "Die error <br>";
die( print_r( sqlsrv_errors(), true));
}
if (sqlsrv_execute($stmt) === false) {
echo "Die error <br>";
die( print_r( sqlsrv_errors(), true));
}
echo "<br><h3>Success</h3><br>";
$data = array();
do {
while ($row = sqlsrv_fetch_array($stmt)) {
$data[] = $row;
}
} while (sqlsrv_next_result($stmt));
return $data;
}
?>
我正在尝试使用 PHP 和 SQL 服务器显示存储过程的输出。存储过程是一个 SELECT
语句。截至目前,我最终处于显示成功消息的 else
条件,但我无法显示查询结果。这是函数:
function account_search_sp($account_number,$occupant_code,$name,$address,$bill_code,$utility_code){
global $db;
sqlsrv_configure("WarningsReturnAsErrors", 0);
$sql = "EXEC sp_cigar_account_search @AcctNo= ?, @OccupantCode= ?, @Name= ?, @Address= ?, @BillCode= ?, @UtilityType= ?";
$procedure_params = array(
array(&$account_number, SQLSRV_PARAM_IN),
array(&$occupant_code, SQLSRV_PARAM_IN),
array(&$name, SQLSRV_PARAM_IN),
array(&$address, SQLSRV_PARAM_IN),
array(&$bill_code, SQLSRV_PARAM_IN),
array(&$utility_code, SQLSRV_PARAM_IN)
);
$stmt = sqlsrv_prepare($db, $sql, $procedure_params);
$result = sqlsrv_execute($stmt);
if( !$result ) {
//Show errors
echo "Die error <br>";
die( print_r( sqlsrv_errors(), true));
}else{
echo "<br><h3>Success</h3><br>";
sqlsrv_next_result($stmt);
}
return $stmt; }
如果我 运行 SSMS 中的存储过程例如使用 200 作为帐号,我会取回数据。
我正在使用 PHP 7.4
感谢任何帮助。如果我需要包含更多信息,请告诉我。
如果我理解正确,您需要使用 sqlsrv_ferch_array()
或 sqlsrv_fetch_object()
:
<?
function account_search_sp($account_number, $occupant_code, $name, $address, $bill_code, $utility_code) {
global $db;
sqlsrv_configure("WarningsReturnAsErrors", 0);
$sql = "EXEC sp_cigar_account_search @AcctNo= ?, @OccupantCode= ?, @Name= ?, @Address= ?, @BillCode= ?, @UtilityType= ?";
$procedure_params = array(
array(&$account_number, SQLSRV_PARAM_IN),
array(&$occupant_code, SQLSRV_PARAM_IN),
array(&$name, SQLSRV_PARAM_IN),
array(&$address, SQLSRV_PARAM_IN),
array(&$bill_code, SQLSRV_PARAM_IN),
array(&$utility_code, SQLSRV_PARAM_IN)
);
$stmt = sqlsrv_prepare($db, $sql, $procedure_params);
if ($stmt === false) {
echo "Die error <br>";
die( print_r( sqlsrv_errors(), true));
}
if (sqlsrv_execute($stmt) === false) {
echo "Die error <br>";
die( print_r( sqlsrv_errors(), true));
}
echo "<br><h3>Success</h3><br>";
$data = array();
do {
while ($row = sqlsrv_fetch_array($stmt)) {
$data[] = $row;
}
} while (sqlsrv_next_result($stmt));
return $data;
}
?>