如何在 c# sharp 中将 char 数组中的字符向左和向右移动
How to move chars in char array to the left and to the right in c# sharp
伙计们!我有这种情况:给定一个字符串和另外两个字符 X 和 Y。将所有 X 字符移动到字符串的开头,将所有 Y 字符移动到字符串的末尾。字符串中其他字符的顺序保持不变。
我写了两个函数 MoveCharsLeft 和 MoveCharsRight 将 X 向左移动 Y 向右移动,但是出现错误 System.IndexOutOfRangeException: 'Index was outside the bounds of the array.' 这行代码 char toReplace = splitText[charToCheck]; 不知道怎么处理,为了解决这个问题.
大佬们帮我看看,功能应该怎样?
static void Main()
{
string text = Console.ReadLine();
char[] splitText = text.ToCharArray();
string firstLetter = Console.ReadLine();
char[] firstChar = firstLetter.ToCharArray();
string secondLetter = Console.ReadLine();
char[] secondChar = secondLetter.ToCharArray();
char one = firstChar[0];
char two = secondChar[0];
Console.WriteLine(CheckChars(splitText, one, two));
Console.ReadLine();
}
static char[] CheckChars(char[] splitText, char one, char two)
{
for (char letter = 'a'; letter <= 'z'; letter++)
{
if (Array.IndexOf(splitText, one) > -1)
{
MoveCharsLeft(splitText, one);
}
if (Array.IndexOf(splitText, two) > -1)
{
MoveCharsRight(splitText, two);
}
}
return splitText;
}
static void MoveCharsLeft(char[] splitText, char charToCheck)
{
char toReplace = splitText[charToCheck];
char currentLetter = splitText[0];
for (int i = 0; i <= charToCheck; i++)
{
char temporary = splitText[i];
splitText[i] = currentLetter;
currentLetter = temporary;
}
splitText[0] = toReplace;
}
static void MoveCharsRight(char[] splitText, char charToCheck)
{
char toReplace = splitText[charToCheck];
char currentLetter = splitText[-1];
for (int i = 0; i <= charToCheck; i++)
{
char temporary = splitText[i];
splitText[i] = currentLetter;
currentLetter = temporary;
}
splitText[-1] = toReplace;
}
你没有检查你的界限。我会说 CheckChars
方法是多余的,在 MoveCharsLeft
和 MoveCharsRight
中你没有检查你是否还在 splitText
.
中
以下是我的实施方式 MoveCharsLeft
,希望它能为您指明正确的方向。
char[] MoveCharactersLeft(char[] text, char character) {
var lowerCharacter = char.ToLower(character);
var left = new List<char>();
var right = new List<char>();
foreach (var letter in text) {
if (char.ToLower(letter) == lowerCharacter) {
left.Add(letter);
continue;
}
right.Add(letter);
}
left.AddRange(right);
return left.ToArray();
}
这里是 MoveCharactersRight
:
char[] MoveCharactersRight(char[] text, char character) {
var lowerCharacter = char.ToLower(character);
var left = new List<char>();
var right = new List<char>();
foreach (var letter in text) {
if (char.ToLower(letter) == lowerCharacter) {
right.Add(letter);
continue;
}
left.Add(letter);
}
left.AddRange(right);
return left.ToArray();
}
既然你已经拥有了两者,你只需调用 MoveCharsLeft
,然后对 MoveCharsLeft
的结果调用 MoveCharactersRight
。
您可以就地交换它们,尽管这需要大量复制。这是一个将字符从数组中的一个位置移动到另一个位置的函数。您可以在网络和 SO.
上找到几个这样的示例
public static void Move(char[] buffer, int from, int too)
{
if (from == too)
return;
char temp = buffer[from];
if (too < from)
{
Array.Copy(buffer, too, buffer, too + 1, from - too);
}
else
{
Array.Copy(buffer, from + 1, buffer, from, too - from);
}
buffer[too] = temp;
}
然后你只需要遍历数组测试字符,测试它们并将它们移动到正确的位置。这是执行此操作的函数:
public static void ArrangeChars(char[] buffer, char left, char right)
{
int leftIndex = 0;
int rightIndex = buffer.Length - 1;
int i = 0;
while(i <= rightIndex)
{
char ch = buffer[i];
if (ch == left && i > leftIndex)
Move(buffer, i, leftIndex++);
else if (ch == right && i < rightIndex)
Move(buffer, i, rightIndex--);
else
++i;
}
}
这样称呼它:
static void Main(string[] _)
{
char[] data = "test me and move".ToCharArray();
Console.WriteLine(new string(data));
ArrangeChars(data, 'e', 't');
Console.WriteLine("Move 'e' to start, move 't' to end");
Console.WriteLine(new string(data));
}
通常的注意事项适用 - 这尚未经过充分测试,如果您使用它,您应该检查所有边缘情况。
伙计们!我有这种情况:给定一个字符串和另外两个字符 X 和 Y。将所有 X 字符移动到字符串的开头,将所有 Y 字符移动到字符串的末尾。字符串中其他字符的顺序保持不变。 我写了两个函数 MoveCharsLeft 和 MoveCharsRight 将 X 向左移动 Y 向右移动,但是出现错误 System.IndexOutOfRangeException: 'Index was outside the bounds of the array.' 这行代码 char toReplace = splitText[charToCheck]; 不知道怎么处理,为了解决这个问题. 大佬们帮我看看,功能应该怎样?
static void Main()
{
string text = Console.ReadLine();
char[] splitText = text.ToCharArray();
string firstLetter = Console.ReadLine();
char[] firstChar = firstLetter.ToCharArray();
string secondLetter = Console.ReadLine();
char[] secondChar = secondLetter.ToCharArray();
char one = firstChar[0];
char two = secondChar[0];
Console.WriteLine(CheckChars(splitText, one, two));
Console.ReadLine();
}
static char[] CheckChars(char[] splitText, char one, char two)
{
for (char letter = 'a'; letter <= 'z'; letter++)
{
if (Array.IndexOf(splitText, one) > -1)
{
MoveCharsLeft(splitText, one);
}
if (Array.IndexOf(splitText, two) > -1)
{
MoveCharsRight(splitText, two);
}
}
return splitText;
}
static void MoveCharsLeft(char[] splitText, char charToCheck)
{
char toReplace = splitText[charToCheck];
char currentLetter = splitText[0];
for (int i = 0; i <= charToCheck; i++)
{
char temporary = splitText[i];
splitText[i] = currentLetter;
currentLetter = temporary;
}
splitText[0] = toReplace;
}
static void MoveCharsRight(char[] splitText, char charToCheck)
{
char toReplace = splitText[charToCheck];
char currentLetter = splitText[-1];
for (int i = 0; i <= charToCheck; i++)
{
char temporary = splitText[i];
splitText[i] = currentLetter;
currentLetter = temporary;
}
splitText[-1] = toReplace;
}
你没有检查你的界限。我会说 CheckChars
方法是多余的,在 MoveCharsLeft
和 MoveCharsRight
中你没有检查你是否还在 splitText
.
以下是我的实施方式 MoveCharsLeft
,希望它能为您指明正确的方向。
char[] MoveCharactersLeft(char[] text, char character) {
var lowerCharacter = char.ToLower(character);
var left = new List<char>();
var right = new List<char>();
foreach (var letter in text) {
if (char.ToLower(letter) == lowerCharacter) {
left.Add(letter);
continue;
}
right.Add(letter);
}
left.AddRange(right);
return left.ToArray();
}
这里是 MoveCharactersRight
:
char[] MoveCharactersRight(char[] text, char character) {
var lowerCharacter = char.ToLower(character);
var left = new List<char>();
var right = new List<char>();
foreach (var letter in text) {
if (char.ToLower(letter) == lowerCharacter) {
right.Add(letter);
continue;
}
left.Add(letter);
}
left.AddRange(right);
return left.ToArray();
}
既然你已经拥有了两者,你只需调用 MoveCharsLeft
,然后对 MoveCharsLeft
的结果调用 MoveCharactersRight
。
您可以就地交换它们,尽管这需要大量复制。这是一个将字符从数组中的一个位置移动到另一个位置的函数。您可以在网络和 SO.
上找到几个这样的示例 public static void Move(char[] buffer, int from, int too)
{
if (from == too)
return;
char temp = buffer[from];
if (too < from)
{
Array.Copy(buffer, too, buffer, too + 1, from - too);
}
else
{
Array.Copy(buffer, from + 1, buffer, from, too - from);
}
buffer[too] = temp;
}
然后你只需要遍历数组测试字符,测试它们并将它们移动到正确的位置。这是执行此操作的函数:
public static void ArrangeChars(char[] buffer, char left, char right)
{
int leftIndex = 0;
int rightIndex = buffer.Length - 1;
int i = 0;
while(i <= rightIndex)
{
char ch = buffer[i];
if (ch == left && i > leftIndex)
Move(buffer, i, leftIndex++);
else if (ch == right && i < rightIndex)
Move(buffer, i, rightIndex--);
else
++i;
}
}
这样称呼它:
static void Main(string[] _)
{
char[] data = "test me and move".ToCharArray();
Console.WriteLine(new string(data));
ArrangeChars(data, 'e', 't');
Console.WriteLine("Move 'e' to start, move 't' to end");
Console.WriteLine(new string(data));
}
通常的注意事项适用 - 这尚未经过充分测试,如果您使用它,您应该检查所有边缘情况。