计算单个查询中表中所有列的列中的不同值

Question

一种快速有效的方法来计算 table 中所有列的列中的不同值。在单个查询中

请注意

我有只读权限。
在一个模式中我有多个 tables，我想计算一些 tables 但不是全部

Answer 1

您可以使用此查询来计算单个列的不同值。（参考查询 1）
对于多列，您必须使用 union all。（参考查询 2）

查询 1 - Select 与 Your_ColumnName 不同，Your_TableName 的计数 (*) 按 Your_ColumnName

分组

查询 2 - Select 不同的 Your_ColumnName1，Your_TableName 的计数（）按 Your_ColumnName1 分组联合所有 Select distinct Your_ColumnName2, count() from Your_TableName group by Your_ColumnName2

Answer 2

我假设最困难的情况 - 当您不能依赖 table 名称的子字符串时。

在这种情况下 - 创建您的 schema/table 列表，并使用它来创建一个脚本来构建一个大脚本，您可以在生成后最终启动该脚本：

CREATE LOCAL TEMPORARY TABLE srch(table_schema,table_name) 
ON COMMIT PRESERVE ROWS AS
          SELECT 'public','gen_sample'
UNION ALL SELECT 'public','d_product'
UNION ALL SELECT 'dbadmin','d_cust_scd'
UNION ALL SELECT 'dbadmin','currencies'
;

SELECT
    CASE ROW_NUMBER() OVER(ORDER BY c.table_schema,c.table_name,ordinal_position)
    WHEN 1 THEN ''
    ELSE 'UNION ALL '
    END
  ||'SELECT '''||c.table_schema||'.'||c.table_name||'.'||column_name||''','
  ||'COUNT(DISTINCT '||column_name||') FROM '||c.table_schema||'.'||c.table_name
FROM columns c JOIN srch USING(table_schema,table_name);

-- out  SELECT 'dbadmin.currencies.id',COUNT(DISTINCT id) FROM dbadmin.currencies
-- out  UNION ALL SELECT 'dbadmin.currencies.nm',COUNT(DISTINCT nm) FROM dbadmin.currencies
-- out  UNION ALL SELECT 'dbadmin.currencies.sgn',COUNT(DISTINCT sgn) FROM dbadmin.currencies
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_key',COUNT(DISTINCT cust_key) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_id',COUNT(DISTINCT cust_id) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_from_dt',COUNT(DISTINCT cust_from_dt) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_to_dt',COUNT(DISTINCT cust_to_dt) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_is_curr',COUNT(DISTINCT cust_is_curr) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_cre_ts',COUNT(DISTINCT cust_cre_ts) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_udt_ts',COUNT(DISTINCT cust_udt_ts) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_fname',COUNT(DISTINCT cust_fname) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_lname',COUNT(DISTINCT cust_lname) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_phoneno',COUNT(DISTINCT cust_phoneno) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_loy_lvl',COUNT(DISTINCT cust_loy_lvl) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'dbadmin.d_cust_scd.cust_org_id',COUNT(DISTINCT cust_org_id) FROM dbadmin.d_cust_scd
-- out  UNION ALL SELECT 'public.d_product.prdkey',COUNT(DISTINCT prdkey) FROM public.d_product
-- out  UNION ALL SELECT 'public.d_product.prdid',COUNT(DISTINCT prdid) FROM public.d_product
-- out  UNION ALL SELECT 'public.d_product.start_date',COUNT(DISTINCT start_date) FROM public.d_product
-- out  UNION ALL SELECT 'public.d_product.end_date',COUNT(DISTINCT end_date) FROM public.d_product
-- out  UNION ALL SELECT 'public.d_product.price',COUNT(DISTINCT price) FROM public.d_product
-- out  UNION ALL SELECT 'public.gen_sample.srr_key',COUNT(DISTINCT srr_key) FROM public.gen_sample
-- out  UNION ALL SELECT 'public.gen_sample.seq',COUNT(DISTINCT seq) FROM public.gen_sample
-- out  UNION ALL SELECT 'public.gen_sample.nucleotide',COUNT(DISTINCT nucleotide) FROM public.gen_sample
-- out  UNION ALL SELECT 'public.gen_sample.quality',COUNT(DISTINCT quality) FROM public.gen_sample

计算单个查询中表中所有列的列中的不同值

count distinct values in column for all columns in a tables in single query

sql

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