presto sql 查找具有按顺序插入的特定列值的 ID

Question

我有一个table

user_id  user_type   date_updated

1         Beginner   10/10/2020
1         Moderate   10/11/2020
1         Advanced   10/12/2020
2         Beginner   10/10/2020
2         Moderate   10/11/2020
2         Expert     10/12/2020
2         Advanced   10/13/2020

我正在寻找 sql 以找到 user_ids 和 user_type（初学者- >Moderate->Advanced) 按 date_updated 顺序递增排列。

上面的结果 table 应该是 user_id 1 因为它有 Beginner(10/10/2020) -> Moderate(10/11/2020) -> Advanced(10/12/ 2020)

user_id 2 不合格，因为所有要求的类型都没有相互遵循 Beginner->Moderate->Expert->高级

Answer 1

一种方法是在 having:

中使用条件逻辑进行聚合

select user_id
from t
group by user_id
having max(case when user_type = 'Beginner' then date_updated end) < max(case when user_type = 'Moderate' then date_updated end) and
       max(case when user_type = 'Moderate' then date_updated end) < max(case when user_type = 'Advanced' then date_updated end);

编辑：

根据修改后的问题，使用lag()。假设给定用户没有重复的用户类型：

select user_id
from (select t.*,
             lag(user_type) over (partition by user_id order by date_updated) as prev_user_type,
             lag(user_type, 2) over (partition by user_id order by date_updated) as prev2_user_type
      from t
     ) t
where prev2_user_type = 'Beginner' and
      prev_user_type = 'Moderate' and
      user_type = 'Advanced'

Answer 2

一种方法使用聚合：

select user_id
from mytable
group by user_id
having array_agg(user_type order by date_updated) = array['Beginner', 'Moderate', 'Advanced']

presto sql 查找具有按顺序插入的特定列值的 ID

presto sql to find ids having specific column values inserted in sequence

sql

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