使用 yq 修改 YAML 以在元数据中的每个条目下包含标签

Question

我有一个类似 below.This 的 yaml 文件需要在每个 configmap 下使用新标签进行修补。

apiVersion: v1
kind: ConfigMapList
items:
  - apiVersion: v1
    data:
      test: 1
    kind: ConfigMap
    metadata:
      name: grafana-dashboard-apiserver1
      namespace: monitoring   
  - apiVersion: v1
    data:
      test: 2
    kind: ConfigMap
    metadata:
      name: grafana-dashboard-apiserver2
      namespace: monitoring   
  - apiVersion: v1
    data:
      test: 3
    kind: ConfigMap
    metadata:
      name: grafana-dashboard-apiserver3
      namespace: monitoring

我想在这个 configmaplist 中的每个 configmap 下插入标签，如下所示，

apiVersion: v1
kind: ConfigMapList
items:
  - apiVersion: v1
    data:
      test: 1
    kind: ConfigMap
    metadata:
      name: grafana-dashboard-apiserver1
      namespace: monitoring
      labels:
        grafana_dashboard: "1"   
  - apiVersion: v1
    data:
      test: 2
    kind: ConfigMap
    metadata:
      name: grafana-dashboard-apiserver2
      namespace: monitoring   
      labels:
        grafana_dashboard: "1" 
  - apiVersion: v1
    data:
      test: 3
    kind: ConfigMap
    metadata:
      name: grafana-dashboard-apiserver3
      namespace: monitoring    
      labels:
        grafana_dashboard: "1"

我不确定如何在 bash 中执行此操作。请帮助我如何执行此操作 bash。yq 有帮助吗？或 Kustomize？

Answer 1

如果您正在使用 mikefarah/yq, you can use the following path expression to write on all metadata fields under the array of items

yq w yaml 'items[*].metadata.labels.grafana_dashboard' --tag '!!str' 1

如果生成的 YAML 输出符合预期，您可以 write in-place 使用 -i 标志，即 yq w -i '..'

使用 yq 修改 YAML 以在元数据中的每个条目下包含标签

Modify YAML to include label under each entry in metadata using yq

yaml

yq