时间序列的 Seaborn 绘图周期

Question

我怎样才能实现类似于：

sns.lineplot(d['month'], d[variable], hue=d['year'], palette=palette)
https://deffro.github.io/time%20series/exploratory%20data%20analysis/data%20visualization/time-series-analysis/

为了我自己的数据？目前，我只能将系列绘制成彼此相邻而不是堆叠：

sns.lineplot(x='hour', y='metrik_0', hue='day_of_week', data=df)

其他也没有帮助解决任务的变体：

# but at least day_of_week is now x and in theory it is plotting the others on top of it
sns.lineplot(x='day_of_week', y='metrik_0', hue='hour', data=df, legend=None)

数据定义为：

import pandas as pd
import numpy as np

import random
random_seed = 47
np.random.seed(random_seed)
random.seed(random_seed)
%pylab inline
import seaborn as sns; sns.set()
import matplotlib.dates as mdates

aut_locator = mdates.AutoDateLocator(minticks=3, maxticks=7)
aut_formatter = mdates.ConciseDateFormatter(aut_locator)


def generate_df_for_device(n_observations, n_metrics, device_id, geo_id, topology_id, cohort_id):
        df = pd.DataFrame(np.random.randn(n_observations,n_metrics), index=pd.date_range('2020', freq='H', periods=n_observations))
        df.columns = [f'metrik_{c}' for c in df.columns]
        df['geospatial_id'] = geo_id
        df['topology_id'] = topology_id
        df['cohort_id'] = cohort_id
        df['device_id'] = device_id
        return df
    
def generate_multi_device(n_observations, n_metrics, n_devices, cohort_levels, topo_levels):
    results = []
    for i in range(1, n_devices +1):
        #print(i)
        r = random.randrange(1, n_devices)
        cohort = random.randrange(1, cohort_levels)
        topo = random.randrange(1, topo_levels)
        df_single_dvice = generate_df_for_device(n_observations, n_metrics, i, r, topo, cohort)
        results.append(df_single_dvice)
        #print(r)
    return pd.concat(results)

# hourly data, 1 week of data
n_observations = 7 * 24
n_metrics = 3
n_devices = 20
cohort_levels = 3
topo_levels = 5

df = generate_multi_device(n_observations, n_metrics, n_devices, cohort_levels, topo_levels)
df = df.sort_index()
df = df.reset_index().rename(columns={'index':'hour'})
df['day_of_week'] = df.hour.dt.dayofweek
sns.lineplot(x='hour', y='metrik_0', hue='day_of_week', data=df)

Answer 1

您的数据是一个时间序列，但它不是您期望的输出格式，因为日期段是连续的。

Assigning the units variable will plot multiple lines without applying a semantic mapping: I'm quoting from the official reference.

sns.lineplot(x='hour', y='metrik_0', hue='day_of_week', units='day_of_week', estimator=None, data=df)

sns.lineplot(x=df['hour'].dt.hour, y='metrik_0', hue='day_of_week',units='day_of_week', estimator=None, data=df)

时间序列的 Seaborn 绘图周期

Seaborn plot periodicities of time series

python

time-series

matplotlib

seaborn

periodicity