在嵌套字典中切换两个字典

Question

我正在尝试在另一个词典中交换两个词典。
我希望看到以下结果：

input: {10: {"name": "name_value1", "price1": "price_value1"}, 
        30: {"name": "name_value3", "price3": "price_value3"}, 
        20: {"name": "name_value2", "price2": "price_value2"}}

output:{10: {"name": "name_value1", "price1": "price_value1"}, 
        20: {"name": "name_value2", "price2": "price_value2"}, 
        30: {"name": "name_value3", "price3": "price_value3"}}

我尝试了很多不同的方法，有时值的顺序是正确的，但键没有更新。下面的代码就是一个例子。

def my_sort(dct):
    index = 0
    key_list = list(dct.keys())
    while index < (len(dct) - 1):
        if key_list[index] > key_list[index + 1]:
            dct[key_list[index]], dct[key_list[index + 1]] = dct[key_list[index + 1]], dct[key_list[index]]
            key_list[index], key_list[index + 1] = key_list[index + 1], key_list[index]
            index = 0
        else:
            index += 1
            
    return dct

此代码输出以下内容：

{10: {"name": "name_value1", "price1": "price_value1"}, 
 30: {"name": "name_value2", "price2": "price_value2"}, 
 20: {"name": "name_value3", "price3": "price_value3"}}

注意：我不能为此使用外部库/框架，也不能使用像 sorted() 这样的函数。

欢迎所有帮助和建议！提前谢谢你。

Answer 1

你可以使用 sorted() 吗？

d = {10: {"name": "name_value1", "price1": "price_value1"},
        30: {"name": "name_value3", "price3": "price_value3"},
        20: {"name": "name_value2", "price2": "price_value2"}}

dict(sorted(d.items(), reverse=False))

输出：

{10: {'name': 'name_value1', 'price1': 'price_value1'},
 20: {'name': 'name_value2', 'price2': 'price_value2'},
 30: {'name': 'name_value3', 'price3': 'price_value3'}}

Answer 2

您可以使用所需的键顺序创建新词典：

old_dict = {10: {"name": "name_value1", "price1": "price_value1"}, 
        30: {"name": "name_value3", "price3": "price_value3"}, 
        20: {"name": "name_value2", "price2": "price_value2"}}

key_ix = [10, 20, 30]
new_dict = {k: old_dict[k] for k in key_ix}

Answer 3

def sort_keys(keys_):
  for i in range(len(keys_)):
    for j in range(i, len(keys_)):
      if keys_[i]  > keys_[j]:
        keys_[i], keys_[j] = keys_[j], keys_[i]
  return keys_

input = {10: {"name": "name_value1", "price1": "price_value1"}, 
        30: {"name": "name_value3", "price3": "price_value3"}, 
        20: {"name": "name_value2", "price2": "price_value2"}}

keys_ = list(input.keys())
sorted_keys = sort_keys(keys_)
out = {key:input[key] for key in sorted_keys}

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