AttributeError: 'dict' object has no attribute (...) when iterate over a dictionary of sets

Question

我试图从他的邻接表表示的无向图中删除一个节点，但我收到了一个我无法理解的错误。

ugraph 示例：

g1 = {0: set([1]), 1: set([0, 2]), 2: set([1, 3]), 3: set([2]), 4: {5, 6}, 5: {4}, 6: {}}

我正在创建的函数：

def remove_node(ugraph, node):
    """
    :param ugraph: An undirected graph
    :param node: The node that we want to remove
    :return: The undirected graph minus one node :)
    """

    try:
        del ugraph[node]
    except KeyError:
        print "The node is not in the graph" 

    for key in ugraph.keys():
        ugraph[key] = ugraph[key].difference(set([node]))

    return ugraph

这是我的错误：

Traceback (most recent call last):
  File "/home/juan/PycharmProjects/AlgorithmicThinking_week2/resilence.py", line 46, in <module>
    print remove_node(g1, 1)
  File "/home/juan/PycharmProjects/AlgorithmicThinking_week2/resilence.py", line 42, in remove_node
    ugraph[key] = ugraph[key].difference(set([node]))
AttributeError: 'dict' object has no attribute 'difference'

为什么会这样？

Answer 1

其中一件与另一件不同：

>>> g1 = {0: set([1]), 1: set([0, 2]), 2: set([1, 3]), 3: set([2]), 4: {5, 6}, 5: {4}, 6: {}}
>>> for key in g1: 
...     print key, g1[key], type(g1[key])
...
0 set([1]) <type 'set'>
1 set([0, 2]) <type 'set'>
2 set([1, 3]) <type 'set'>
3 set([2]) <type 'set'>
4 set([5, 6]) <type 'set'>
5 set([4]) <type 'set'>
6 {} <type 'dict'>

{} 是空字典，不是空集。请改用 set()。

AttributeError: 'dict' object has no attribute (...) when iterate over a dictionary of sets

AttributeError: 'dict' object has no attribute (...) when iterate over a dictionary of sets

graph

attributeerror

pycharm

python-2.7