Return Prolog 中两个函数的值相等

Question

我有一个电影数据库，其中包含

movie(blood_simple, 1984).
movie(the_cotton_club, 1984).
movie(american_beauty, 1999).
...

我想编写一个函数，如果给定的两部电影在同一年上映，则 returns 为真，否则为假。

我在比较两个值时遇到问题，我的函数总是 returns false。

这是我的代码：

sameyear(Movie1,Movie2):-
    movie(Movie1,Year1),
    movie(Movie2,Year2).
    % here I tried comparing Year1 with Year2 like: Year1 == Year2, Year1 =:= Year2, nothing worked.

另一个代码：

sameyear(Movie1,Movie2):-
    movie(Movie1,Year1),
    movie(Movie2,Year1).    % here I expected that it would return true if the movies were released at the
 same year, because Year1 has already got a value at *movie(Movie1,Year1)*, but that didn't happen

你能帮帮我吗？

Answer 1

您在 movie(Movie2, Year2) 子句的末尾写了一个点 (.)。因此，这意味着您结束了谓词。如果你再写Year1 == Year2.，那么这是另一个规则。

因此您应该使用逗号，它在语义上接近 逻辑和:

sameyear(Movie1,Movie2):-
    movie(Movie1,Year1),
    movie(Movie2,Year2)<b>,</b>  % ← added a comma
    Year1 == Year2.

然后生成：

?- sameyear(M1, M2).
M1 = M2, M2 = blood_simple ;
M1 = blood_simple,
M2 = the_cotton_club ;
M1 = the_cotton_club,
M2 = blood_simple ;
M1 = M2, M2 = the_cotton_club ;
M1 = M2, M2 = american_beauty.

Return Prolog 中两个函数的值相等

Return value of two functions are equal in Prolog

prolog

comparison