将数据库身份验证添加到 Spring Data Rest 应用程序
Add database authentication to Spring Data Rest application
我正在使用 Spring Data REST with Thymeleaf 创建一个应用程序。
最初我创建了我的模型、控制器、dao 和服务。一切正常。我现在正在尝试为我的应用程序添加安全性。现在我只关注 login/logout.
我已经能够如下创建内存中身份验证:
@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
@Qualifier("securityDataSource")
private DataSource securityDataSource;
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
// add users for in memory authentication
UserBuilder users = User.withDefaultPasswordEncoder();
auth.inMemoryAuthentication()
.withUser(users.username("paul").password("test123").roles("MEMBER", "ADMIN"))
.withUser(users.username("sandra").password("test123").roles("MEMBER", "ADMIN"))
.withUser(users.username("matthew").password("test123").roles("MEMBER"));
}
}
不过我想将其更改为数据库身份验证。我很确定我可以创建一个 jdbc 连接并将我的配置方法更改为如下所示:
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.jdbcAuthentication().dataSource(securityDataSource);
}
我的问题是我已经在通过我的 DAO 接口访问数据库了。例如:
public interface UserRepository extends JpaRepository<User, Integer> {
// method to sort by last name
public List<User> findAllByOrderByLastNameAsc();
}
我的用户 table 有一个电子邮件和密码列,将用作 username/password。
是否也可以通过某种方式使用它来进行身份验证?我可以提供额外的信息,但我不愿意只 post 一切,希望有人能帮我写。
假设db table name 是用户和权限。数据源配置在application.yml.
@Autowired
private DataSource dataSource;
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.jdbcAuthentication()
.dataSource(dataSource)
.usersByUsernameQuery("select username,password,enabled from users WHERE username=?")
.authoritiesByUsernameQuery("select username,authority from authorities where username=?")
.passwordEncoder(new BCryptPasswordEncoder());
}
}
由于您已经创建了 DAO 接口,因此创建起来可能更容易
UserDetailsService
实施:
@Service
@NoArgsConstructor @ToString @Log4j2
public class UserDetailsServiceImpl implements UserDetailsService {
@Autowired private UserRepository userRepository = null;
@Override
@Transactional(readOnly = true)
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
org.springframework.security.core.userdetails.User user = null;
try {
Optional<User> optional = userRepository.findBy...(username);
HashSet<GrantedAuthority> set = new HashSet<>();
/*
* Add SimpleGrantedAuthority to set as appropriate
*/
user = new org.springframework.security.core.userdetails.User(username, optional.get().getPassword(), set);
} catch (UsernameNotFoundException exception) {
throw exception;
} catch (Exception exception) {
throw new UsernameNotFoundException(username);
}
return user;
}
}
并将其连接到:
@Autowired private UserDetailsService userDetailsService = null;
... private PasswordEncoder passwordEncoder = ...;
@Override
public void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.userDetailsService(userDetailsService)
.passwordEncoder(passwordEncoder);
}
为了更加清楚,这里是我实施的完整上下文:
@Service
@NoArgsConstructor @ToString @Log4j2
public class UserDetailsServiceImpl implements UserDetailsService {
@Autowired private CredentialRepository credentialRepository = null;
@Autowired private AuthorityRepository authorityRepository = null;
@Override
@Transactional(readOnly = true)
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
User user = null;
try {
Optional<Credential> credential = credentialRepository.findById(username);
Optional<Authority> authority = authorityRepository.findById(username);
HashSet<GrantedAuthority> set = new HashSet<>();
if (authority.isPresent()) {
authority.get().getGrants().stream()
.map(Authorities::name)
.map(SimpleGrantedAuthority::new)
.forEach(set::add);
}
user = new User(username, credential.get().getPassword(), set);
} catch (UsernameNotFoundException exception) {
throw exception;
} catch (Exception exception) {
throw new UsernameNotFoundException(username);
}
return user;
}
}
我正在使用 Spring Data REST with Thymeleaf 创建一个应用程序。
最初我创建了我的模型、控制器、dao 和服务。一切正常。我现在正在尝试为我的应用程序添加安全性。现在我只关注 login/logout.
我已经能够如下创建内存中身份验证:
@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
@Qualifier("securityDataSource")
private DataSource securityDataSource;
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
// add users for in memory authentication
UserBuilder users = User.withDefaultPasswordEncoder();
auth.inMemoryAuthentication()
.withUser(users.username("paul").password("test123").roles("MEMBER", "ADMIN"))
.withUser(users.username("sandra").password("test123").roles("MEMBER", "ADMIN"))
.withUser(users.username("matthew").password("test123").roles("MEMBER"));
}
}
不过我想将其更改为数据库身份验证。我很确定我可以创建一个 jdbc 连接并将我的配置方法更改为如下所示:
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.jdbcAuthentication().dataSource(securityDataSource);
}
我的问题是我已经在通过我的 DAO 接口访问数据库了。例如:
public interface UserRepository extends JpaRepository<User, Integer> {
// method to sort by last name
public List<User> findAllByOrderByLastNameAsc();
}
我的用户 table 有一个电子邮件和密码列,将用作 username/password。
是否也可以通过某种方式使用它来进行身份验证?我可以提供额外的信息,但我不愿意只 post 一切,希望有人能帮我写。
假设db table name 是用户和权限。数据源配置在application.yml.
@Autowired
private DataSource dataSource;
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.jdbcAuthentication()
.dataSource(dataSource)
.usersByUsernameQuery("select username,password,enabled from users WHERE username=?")
.authoritiesByUsernameQuery("select username,authority from authorities where username=?")
.passwordEncoder(new BCryptPasswordEncoder());
}
}
由于您已经创建了 DAO 接口,因此创建起来可能更容易
UserDetailsService
实施:
@Service
@NoArgsConstructor @ToString @Log4j2
public class UserDetailsServiceImpl implements UserDetailsService {
@Autowired private UserRepository userRepository = null;
@Override
@Transactional(readOnly = true)
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
org.springframework.security.core.userdetails.User user = null;
try {
Optional<User> optional = userRepository.findBy...(username);
HashSet<GrantedAuthority> set = new HashSet<>();
/*
* Add SimpleGrantedAuthority to set as appropriate
*/
user = new org.springframework.security.core.userdetails.User(username, optional.get().getPassword(), set);
} catch (UsernameNotFoundException exception) {
throw exception;
} catch (Exception exception) {
throw new UsernameNotFoundException(username);
}
return user;
}
}
并将其连接到:
@Autowired private UserDetailsService userDetailsService = null;
... private PasswordEncoder passwordEncoder = ...;
@Override
public void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.userDetailsService(userDetailsService)
.passwordEncoder(passwordEncoder);
}
为了更加清楚,这里是我实施的完整上下文:
@Service
@NoArgsConstructor @ToString @Log4j2
public class UserDetailsServiceImpl implements UserDetailsService {
@Autowired private CredentialRepository credentialRepository = null;
@Autowired private AuthorityRepository authorityRepository = null;
@Override
@Transactional(readOnly = true)
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
User user = null;
try {
Optional<Credential> credential = credentialRepository.findById(username);
Optional<Authority> authority = authorityRepository.findById(username);
HashSet<GrantedAuthority> set = new HashSet<>();
if (authority.isPresent()) {
authority.get().getGrants().stream()
.map(Authorities::name)
.map(SimpleGrantedAuthority::new)
.forEach(set::add);
}
user = new User(username, credential.get().getPassword(), set);
} catch (UsernameNotFoundException exception) {
throw exception;
} catch (Exception exception) {
throw new UsernameNotFoundException(username);
}
return user;
}
}