Android Json 对象放置一个没有键的数组 JSON
Android Json Object put a Array JSON without key
我需要用结构
创建一个json
{
"label": "any description",
"location":[25.7752965,-100.2636682]
}
Json 带数组但没有键、值(位置)的对象,
我试试
String[] _location = new String[2];
_location[0] = String.valueOf(latLng.latitude);
_location[1] = String.valueOf(latLng.longitude);
JSONObject params = new JSONObject();
params.put("location",_location);
params.put("label",_label);
另一个尝试使用:
JsonObject obj = new JsonObject();
JsonArray array_location = new JsonArray();
array_location.add(currentLocation.latitude);
array_location.add(currentLocation.longitude);
JSONObject params = new JSONObject();
params.put("location",_location);
params.put("label",_label);
但是,结果给了我一个带有字符串值的 json...当我需要一个值为 Array double
的键“位置”时
{
"label": "any description",
"location":"[25.7752965,-100.2636682]"
}
解决方案
JSONObject params = new JSONObject();
params.put("label", "any description");
JSONArray locationJsonArray = new JSONArray();
locationJsonArray.put(25.775296); // Replace by your latitude
locationJsonArray.put(-100.2636682); // Replace by your longitude
params.put("location", locationJsonArray);
// For debug purpose
Log.i("DEBUG", params.toString(4));
结果
{
"label": "any description",
"location": [
25.775296,
-100.2636682
]
}
我需要用结构
创建一个json {
"label": "any description",
"location":[25.7752965,-100.2636682]
}
Json 带数组但没有键、值(位置)的对象,
我试试
String[] _location = new String[2];
_location[0] = String.valueOf(latLng.latitude);
_location[1] = String.valueOf(latLng.longitude);
JSONObject params = new JSONObject();
params.put("location",_location);
params.put("label",_label);
另一个尝试使用:
JsonObject obj = new JsonObject();
JsonArray array_location = new JsonArray();
array_location.add(currentLocation.latitude);
array_location.add(currentLocation.longitude);
JSONObject params = new JSONObject();
params.put("location",_location);
params.put("label",_label);
但是,结果给了我一个带有字符串值的 json...当我需要一个值为 Array double
的键“位置”时 {
"label": "any description",
"location":"[25.7752965,-100.2636682]"
}
解决方案
JSONObject params = new JSONObject();
params.put("label", "any description");
JSONArray locationJsonArray = new JSONArray();
locationJsonArray.put(25.775296); // Replace by your latitude
locationJsonArray.put(-100.2636682); // Replace by your longitude
params.put("location", locationJsonArray);
// For debug purpose
Log.i("DEBUG", params.toString(4));
结果
{
"label": "any description",
"location": [
25.775296,
-100.2636682
]
}