func form.is_valid() return 始终为 False

Question

我有一个表单，它从用户模型和我自己的“电子邮件”字段中获取“用户名”。我想为用户模型更改此数据。乍一看一切似乎都很好，名称改变了，邮件是一样的。但是，如果我只更改邮件而不触及用户名，则会收到错误消息：“具有此名称的用户已存在。

文件views.py:

form=UserUpdateForm(request.POST)
if form.is_valid():
    user=User.objects.get(username=self.request.user)
    user.username=form.cleaned_data.get('username')
    user.email=form.cleaned_data.get('email')
    user.save()

文件forms.py:

class UserUpdateForm(forms.ModelForm):
    email = forms.EmailField(required=False)
    def __init__(self,  *args, **kwargs):
        super(UserUpdateForm, self).__init__(*args, **kwargs)
        if 'label_suffix' not in kwargs:
            kwargs['label_suffix'] = '*'
        self.fields['username'].widget = forms.TextInput(attrs={'class':'input-text'})
        self.fields['email'].widget = forms.EmailInput(attrs={'class':'input-text'})
    class Meta:
        model = User
        fields = ("username","email",)
    def clean_email(self):
        cleaned_data = super(UserUpdateForm,self).clean() 
        email=cleaned_data.get('email')
        return email

Answer 1

来自doc,

A subclass of ModelForm can accept an existing model instance as the keyword argument instance; if this is supplied, save() will update that instance. If it’s not supplied, save() will create a new instance of the specified model

如果您正在更新数据，您必须将实例传递给表单，

# on updationg
form = UserUpdateForm(data= request.POST, <b>instance=your_mode_instance</b>)

因为你不是第二次传递实例，Django认为这个操作是行插入而不是行更新

func form.is_valid() return 始终为 False

func form.is_valid() return all time False

django

django-forms

django-validation